3 years ago

What is the amplitude of the following function:f(x) = 5 cos x***

Mathematics

1 answer:

Reika [66]3 years ago

7 0

The amplitude here would be 5

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When working with inequalities what do you do when its x squared > 16 and vice versa does the sign flip.

S_A_V [24]

Answer:

$x4$

$\{x\in \mathbb{R}| \:\left(-\infty \:,\:-4\right)\cup \left(4,\:\infty \:\right) \}$

Step-by-step explanation:

$x^2>16$

$x\sqrt{16}$

$x4$

The interval notation will be:

$\{x\in \mathbb{R}| \:\left(-\infty \:,\:-4\right)\cup \left(4,\:\infty \:\right) \}$

The contrary,

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is $-4$

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11x2 would be your answer.

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Find the output, kkk, when the input, ttt, is -7−7minus, 7.<br> k = 10t-19k=10t−19

Sati [7]

The output k at input t = -7 is -89

Step-by-step explanation:

In order to find the value of a expression on given number, we put the number in given expression in place of independent variable

So,

Given expression is:

$k = 10t-19$

It is given that the value of t has to be -7

so putting t=-7 in the expression

$k = 10(-7)-19\\k = -70-19\\k = -89$

Hence,

The output k at input t = -7 is -89

Keywords: Expressions, input, output

Learn more about expressions at:

#LearnwithBrainly

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Please help!! i also need to show work. <br><br><br> write in vertex form y = -3x^2 - 18x + 12

LuckyWell [14K]

Answer:

3(-x^2-6x+4)

Step-by-step explanation:

-3x^2 - 18x + 12

-3x^2 - (2 x 3^2) x + 2^2 x 3

3 (-3x^2 over 3 - 2x3^2 times x over 3 + 262 x 3 over 3)

3(-(x^2) - (2 x 3^2-1 times x) +2^2

3(-x^2 - (2 times 3x) +4)

3(-x^2-(6x) + 4)

3(-x^2 - 6x + 4)

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