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Harrizon [31]
3 years ago
6

The following is an arithmetic sequence. 2, 4, -9, 5 TRUE FALSE

Mathematics
1 answer:
Leno4ka [110]3 years ago
8 0
True or false.. it would be False
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the Answer is -1 think

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7. Two rectangles were used to form the following figure. The dimensions of both rectangles have been provided to the nearest ha
Irina-Kira [14]

Answer:

b

Step-by-step explanation:

edmentum

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3 years ago
How many 10-digit ternary strings are there that contain exactly two 0s, three 1s, and five 2s?
Svet_ta [14]

There are \dbinom{10}2 ways of picking 2 of the 10 available positions for a 0. 8 positions remain.

There are \dbinom83 ways of picking 3 of the 8 available positions for a 1. 5 positions remain, but we're filling all of them with 2s, and there's \dbinom55=1 way of doing that.

So we have

\dbinom{10}2\dbinom83\dbinom55=\dfrac{10!}{2!(10-2)!}\dfrac{8!}{3!(8-3)!}\dfrac{5!}{5!(5-5)!}=2520

The last expression has a more compact form in terms of the so-called multinomial coefficient,

\dbinom{10}{2,3,5}=\dfrac{10!}{2!3!5!}=2520

5 0
3 years ago
What is 7/10+20/100?
Firdavs [7]
9/10. make the bottom numbers the same to add fractions. you can do that by multiplying 7/10 by 10/10.

70/100 + 20/100 = 90/100

90/100 = 9/10

you can also reduce 20/100 to 2/10.

7/10 + 2/10 = 9/10
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3 years ago
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Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th
Sloan [31]

Answer:  3x^2y\sqrt[3]{y}\\\\

Work Shown:

\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

4 0
3 years ago
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