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jekas [21]
3 years ago
12

What is the value of x in log2 (x)-3=1 A) 2^2 b) 2^4 c) 2^3 d) 2^1

Mathematics
2 answers:
djyliett [7]3 years ago
8 0

Domain:x > 0\\\\\log_2x-3=1\qquad\text{add 3 to both sides}\\\\\log_2x=4\qquad\text{use de}\text{finition of logarithm}:\ \log_ab=c\iff a^c=b\\\\\boxed{x=2^4}\to\boxed{b)}

Amiraneli [1.4K]3 years ago
5 0

\log_2 x - 3 = 1

\log_2 x = 4

x = 2^4

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stepladder [879]

Answer:

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4 years ago
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4 years ago
At a pizza resturant they have a choice of 20 toppings. If a customer choosea two topping pizza find the probability that they o
Naddika [18.5K]

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Step-by-step explanation:

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3 0
3 years ago
Number 2 I need help on how to solve it
Hunter-Best [27]

Let's simplify the following expression:

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We get,

\text{ }\frac{(\text{2x}^4\text{ - y}^6\text{z}^{-4})^2}{\text{ 2x}^2\text{z}^3}\text{ }\cdot\text{  }\frac{6x^5y^{-4}z^{-5}}{(2x^6y^3z^{-3})^2}\text{ }\frac{(2x^4-y^6z^{-4})^2(6x^5y^{-4}z^{-5})}{(2x^2z^3)(2x^6y^3z^{-3})^2}\text{ }\frac{(4x^8\text{ - 4x}^4y^6z^{-4}\text{ + y}^{12}z^{-8})(6x^5y^{-4}z^{-5})}{(2x^2z^3)(4x^{12}y^6z^{-6})}\text{ }\frac{24x^{13}y^{-4}z^{-5}\text{ - 24x}^9y^2z^{-9}\text{ + 6x}^5y^8z^{-13}}{8x^{14}y^6z^{-3}}

4 0
1 year ago
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