I'm pretty sure its a^2+b^2=C^2
A part of a line that connects two endpoints I believe
Answer:

Step-by-step explanation:
Eliminating a negative and changing our operation

Rewriting our equation with parts separated

Solving the whole number parts

Solving the fraction parts
![-\frac{5}{6} +\frac{1}{4} =[?]](https://tex.z-dn.net/?f=-%5Cfrac%7B5%7D%7B6%7D%20%2B%5Cfrac%7B1%7D%7B4%7D%20%3D%5B%3F%5D)
Find the LCD of 5/6 and 1/4 and rewrite to solve with the equivalent fractions.
LCD = 12

Combining the whole and fraction parts

[RevyBreeze]
If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4