Solve the equation for x 6x-18-3x<27-2x

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

3 0

Answer:

x<9

Step-by-step explanation:

You might be interested in

2root3 sin^<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ac9eec">[email protected]</a> - <a href

Phantasy [73]

Answer:

Step-by-step explanation:

$2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3}) } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}$

$\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)$

$or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )$

5 0

3 years ago

How many significant figures will there be in the answer to the following

serious [3.7K]

can you show me a picture then maybe i can help you

4 0

3 years ago

Which value of k makes 3- 3k -12 > 9 true ?

Nadya [2.5K]

Answer:

Step-by-step explanation

k can be 11. If u plug 11: 3-21-12 is bigger than 9

3 0

2 years ago

Read 2 more answers

Number 8 pleaseee !!!

MissTica

-6/7 < -6.7

i hope this helps

7 0

3 years ago

Read 2 more answers

What is the equivalent fraction of 60/98

scoray [572]

$\frac{60}{98}=\frac{60:2}{98:2}=\boxed{\frac{30}{49}}\\\\\frac{60}{98}=\frac{60\cdot2}{98\cdot2}=\boxed{\frac{120}{196}}\\\\\frac{60}{98}=\frac{60\cdot3}{98\cdot3}=\boxed{\frac{180}{294}}\\\vdots\\\frac{60}{98}=\frac{60\cdot10}{98\cdot10}=\boxed{\frac{600}{980}}\\\vdots$

7 0

3 years ago