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polet [3.4K]
3 years ago
6

Lia has a bag with 3 spotted, 4 plaid, 1 rainbow, and 4 plain blocks. She draws a block without looking, records what she gets,

and puts the block back in the bag. If she repeats this process 132 times, about how many times should she expect to get a plaid block? I need this right now please. I will give a lot of points.

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0
The image has the answer and the work. 

Hope this helps!

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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B14%7D%20%2F%20%5Cfrac%7B4%7D%7B3%7D" id="TexFormula1" title="\frac{9}{14} / \
Assoli18 [71]
About 0.482
calculator
6 0
3 years ago
Expand the brackets 5(2x + 3)
zimovet [89]

Answer:

10x+15

Step-by-step explanation:

5 x 2x=10x

5x3=15

5 0
3 years ago
Read 2 more answers
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
PLSS HELP ME!! I need to find the value of x
-BARSIC- [3]

Answer:

D. 12°

Step-by-step explanation:

80° + 5x = 140°

or, 5x = 140° - 80°

or, x = 60°/5

:. = 12° <em><u>Ans</u></em>

5 0
3 years ago
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27x + 343 = 0 what’s the imaginary or real solution
Oliga [24]

Answer:

-343/27

Step-by-step explanation:

7 0
2 years ago
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