<span>Let A be the center of a circle and two angles at the adjacent center AOB and BOC. Knowing the measure of the angle AOB = 120 and the measure BOC = 150, find the measures of the angles of the ABC triangle.
</span>solution
Given the above information;
AC=AB, therefore ABC is an isosceles triangle.
therefore, BAO=ABO=(180-120)/2=30
OAC=OCA=(180-90)/2=45
OBC=BCO=(180-150)/2=15
THUS;
BAC=BAO+OAC=45+30=75
ABC=OBA+CBO=15+30=45
ACB=ACO+BCO=15+45=60
Answer and Explanation:
Volume of a cylinder is given by
V= Pi*r²*h
where v= volume of the cylinder
Pi is constant = 22/7 or 3.14159
r= radius of the circle of the cylinder
h= height of the cylinder
If two cylinders are measured proportionally to the other based on radius and height of each cylinder, we look at the proportional equality of the ratio of the radius and height of one cylinder to the other. If one cylinder for example has ratio of radius and height =2/4 then it is proportional to the other cylinder with ratio 1/2
Answer:
Step-by-step explanation:
Yes. The zeroes of a graph are the values of x where the graph touches (or crosses) the x-axis.
Answer:
answer is 94/14
Step-by-step explanation:
you got to make the number into a mixed number but anyways you just mutiply the denominator to the whole number then add the numbrator so you have 58/14+18/7 then in order to add you have to make sure the denominator is the same so change the 18/7 into 14 denominator so u got to mutiply 7 by 2 so u got to do that to the 18 to then finally u add
It is a translation of fx by 5 to the right
