Answer:
Jameel is 13 and Laitfa is 13 x 2 - 10 = 16
16 + 13 = 29
Step-by-step explanation:
The equation has already been given to us, so we just have to solve it.
According to the question,
L + J = 29
L = 2J - 10
L
2J - 10 + J = 29
add 10 both sides
2J + J = 29 + 10 = 39
3J = 39
J = 39/3 = 13
Done!
Answer:
70
Step-by-step explanation:
100 - 2(x + 5) = 100 - 2x - 10 = 90 -2x
90 - 2x
90 - 2×10
90 - 20 = 70
Answer:
7 square units
Step-by-step explanation:
As with many geometry problems, there are several ways you can work this.
Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.
The applicable formulas are ...
area of a trapezoid: A = (1/2)(b1 +b2)h
area of a triangle: A = (1/2)bh
So, our areas are ...
AQRS = AWSQE - AWSR - AEQR
= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)
Factoring out 1/2, we have ...
= (1/2)((2+5)·4 -2·2 -5·2)
= (1/2)(28 -4 -10) = 7 . . . . square units
Answer:
to be honest idek
Step-by-step explanation:
Answer:
Step-by-step explanation:
You have the following differential equation:
This equation can be written as:
where
If the differential equation is exact, it is necessary the following:
Then, you evaluate the partial derivatives:
The partial derivatives are equal, then, the differential equation is exact.
In order to obtain the solution of the equation you first integrate M or N:
(1)
Next, you derive the last equation respect to t:
however, the last derivative must be equal to M. From there you can calculate g(t):
![\frac{\partial F(t,y)}{\partial t}=M=(7y-3t)e^t=7ye^t+g'(t)\\\\g'(t)=-3te^t\\\\g(t)=-3\int te^tdt=-3[te^t-\int e^tdt]=-3[te^t-e^t]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpartial%20F%28t%2Cy%29%7D%7B%5Cpartial%20t%7D%3DM%3D%287y-3t%29e%5Et%3D7ye%5Et%2Bg%27%28t%29%5C%5C%5C%5Cg%27%28t%29%3D-3te%5Et%5C%5C%5C%5Cg%28t%29%3D-3%5Cint%20te%5Etdt%3D-3%5Bte%5Et-%5Cint%20e%5Etdt%5D%3D-3%5Bte%5Et-e%5Et%5D)
Hence, by replacing g(t) in the expression (1) for F(t,y) you obtain:
where C is the constant of integration
