This would be snow falling on a glacier since the cryosphere has to do with frozen water on the surface of earth (AKA Glaciers) and the snow comes from the atmosphere. So we can say that snow and glaciers make an atmosphere-cryoshere interaction.

6 0

3 years ago

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Balance the following equation in basic solution, using the lowest possible integer coefficients. What is the coefficient of wat

zalisa [80]

Answer:

Balanced equation: $2Cr(OH)_{3}(s)+3H_{2}O_{2}(aq.)+4OH^{-}(aq.)\rightarrow 2CrO_{4}^{2-}(aq.)+8H_{2}O(l)$

The coefficient of water is 8

Explanation:

Oxidation: $Cr(OH)_{3}(s)\rightarrow CrO_{4}^{2-}(aq.)$

Balance O and H in basic medium: $Cr(OH)_{3}(s)+5OH^{-}(aq.)\rightarrow CrO_{4}^{2-}(aq.)+4H_{2}O(l)$

Balance charge: $Cr(OH)_{3}(s)+5OH^{-}(aq.)-3e^{-}\rightarrow CrO_{4}^{2-}(aq.)+4H_{2}O(l)$ ......(1)

Reduction: $H_{2}O_{2}(aq.)\rightarrow H_{2}O(l)$

Balance O and H in basic medium: $H_{2}O_{2}(aq.)\rightarrow 2OH^{-}(aq.)$

Balance charge: $H_{2}O_{2}(aq.)+2e^{-}\rightarrow 2OH^{-}(aq.)$ .....(2)

$[2\times equation(1)]+[3\times equation(2)]:$

$2Cr(OH)_{3}(s)+3H_{2}O_{2}(aq.)+4OH^{-}(aq.)\rightarrow 2CrO_{4}^{2-}(aq.)+8H_{2}O(l)$

The coefficient of water is 8.

8 0

3 years ago

A tire contains 1.50 mol of air at a gauge pressure of 205 kPa. If the volume of the air in the tire is 0.0120 m3, what is its t

Free_Kalibri [48]

Answer:

197.07 K

Explanation:

To solve this problem we can use the PV=nRT equation, where:

P = 205 kPa ⇒ 205 * 0.00986 = 2.02 atm

V = 0.0120 m³ ⇒ 0.0120 * 1000 = 12 L

n = 1.50 mol

R = 0.082 atm·L·mol⁻¹·K⁻¹

T = ?

We input the data:

2.02 atm * 12 L = 1.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

And solve for T:

T = 197.07 K

6 0

3 years ago

Calculate the percentage by mass of oxygen in (nh4)2co3

lianna [129]

96.09 g/mol, so weight of Oxygen in the whole thing is 16g/mol*3 = 48.

48/96.09 = around 49.95%

5 0

4 years ago