The curved top of a liquid is the meniscus
Answer:
c = 100 J/g.°C
Explanation:
Given data:
Mass of lime = 20 g
Heat absorbed = 80,000 J
Initial temperature = 10°C
Final temperature = 50°C
Specific heat capacity of lime = ?
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 50°C - 10°C
ΔT = 40°C
80,000 J = 20 g×c×40°C
80,000 J = 800°C×c
c = 80,000 J /800g.°C
c = 100 J/g.°C
