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mr_godi [17]
3 years ago
5

A tire contains 1.50 mol of air at a gauge pressure of 205 kPa. If the volume of the air in the tire is 0.0120 m3, what is its t

emperature
Chemistry
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

197.07 K

Explanation:

To solve this problem we can <u>use the PV=nRT equation</u>, where:

  • P = 205 kPa ⇒ 205 * 0.00986 = 2.02 atm
  • V = 0.0120 m³ ⇒ 0.0120 * 1000 = 12 L
  • n = 1.50 mol
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = ?

We<u> input the data</u>:

  • 2.02 atm * 12 L = 1.50 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * T

And <u>solve for T</u>:

  • T = 197.07 K
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