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3 years ago

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Mathematics

2 answers:

dusya [7]3 years ago

8 0

The equation

$w=112+8t$

means that you choose a value for the input variable t, and you compute the correspondent value for the output variable w.

So, if the input is t = 176, the output will be

$w=112+8\cdot 176 = 112+1408 = 1520$

Similarly, the ordered pair (4, 144) means that if you choose 4 as input, you get 144 as output, in fact you have

$w=112+8\cdot 4= 112+32= 144$

Yuliya22 [10]3 years ago

6 0

Answer:

The first one is 8

The second one is 144

Step-by-step explanation:

I just did it on brainly

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State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

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Answer:

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Step-by-step explanation:

Add all the numbers we know

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133+47=180

47 Your answer. Hope this helped leave a heart or like or comment. :)

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Step-by-step explanation:

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