Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
the answer would be revenue
Answer:
203
Step-by-step explanation:
14×14.50=203 I calculated it
Area of rectangle = 24/54 square miles
length(L) = 5/9 miles
width (W)= ?
area = L * W
25/54 = 5/9 * W
W = (25/54) / (5/9) = (25 * 9) / (54 * 5)
W = 5/6 miles
So, since averages are defined as:

So, since P are the total number of elements and P_k is the P_kth student. This is saying if we sum over each student's score and divide it by the number of students, we should get P, which is true.
So, using that logic, the other class can be represented as:

We can take both of these equations and multiply them by N:


So, if we want to find the average of this we should add both our equations then divide by P+N, which is the number of all the students.

To make this simpler we can replace our LHS with 86, since that's the average of both classes combined.

Simplified we would have P/N=3/8.