Find the rate of interest per annum when 1. P= 900 T= 2 years S.l. = 90
1 answer:
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Answer:
A.
⇒The slope of the function f(x) is greater than the slope of the function g(x).
This is so because using the slope intercept form equation, the slope of f(x) is 6 while that of g(x) is 5
B.
⇒The function f(x) has a greater y-intercept than the function g(x)
⇒The y intercept for the function f(x) is -1 where as that of the function g(x) is -4
Step-by-step explanation:
This question is on the standard equation of a linear function using the slope-intercept form
y=m x+c----------where m is the gradient/slope of the line and c is the y-intercept.
Given the values in function f(x) we can identify the points in the line as;
(-1,-7), (0,-1) , (1,5)............plot the points to obtain the graph as indicated in the attachment.
Find the gradient of the graph ;
m₁=Δy/Δx
m₁= 5--1/1-0 =6/1 =6
Equation of line will be;
y-5/x-1 = 6
y-5=6(x-1)
y-5=6x-6
y=6x-1.........................m₁=6 and c₁= -1
Given that;
g(x)=5x-4.........................m₂=5 c₂= -4
⇒The slope of slope of the function f(x) is greater than the slope of the function g(x).
This is so because using the slope intercept form equation, the slope of f(x) is 6 while that of g(x) is 5
B.
⇒The function f(x) has a greater y-intercept than the function g(x)
⇒The y intercept for the function f(x) is -1 where as that of the function g(x) is -4
In the attached graph;
Red line graph, y=5x-4
Blue line graph, y=6x-1
Answer:
Hence Proved △ SPT ≅ △ UTQ
Step-by-step explanation:
Given: S, T, and U are the midpoints of Segment RP , segment PQ , and segment QR respectively of Δ PQR.
To prove: △ SPT ≅ △ UTQ
Proof:
∵ T is is the midpoint of PQ.
Hence PT = PQ ⇒equation 1
Now,Midpoint theorem is given below;
The Midpoint Theorem states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.
By, Midpoint theorem;
TS║QR
Also,
Hence, TS = QU (U is the midpoint QR) ⇒ equation 2
Also by Midpoint theorem;
TU║PR
Also,
Hence, TU = PS (S is the midpoint QR) ⇒ equation 3
Now in △SPT and △UTQ.
PT = PQ (from equation 1)
TS = QU (from equation 2)
PS = TU (from equation 3)
By S.S.S Congruence Property,
△ SPT ≅ △ UTQ ...... Hence Proved
