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iren2701 [21]
3 years ago
6

The temperature of water in the Solar steam power system for time 0 equal to or less than t equal to or less than 10, is modeled

by the differentiable function S, where t is measured in hours. Selected values of S(t) are given in the table above and represent the temperature in degrees celsius of the water in the solar steam power system.
(a) use the data in the table to evaluate the definitive integral of S'(t)dt where a=10 and b=0. using correct units interpret the meaning of the definitive integral in the context of this problem.
(b) For 0 less than or equal to t less than or equal to 6, approximate the average temperature of the water in the system using a right Riemann approximation. determine if the approximation is an overestimate or an underestimate. justify your answer.
(c) For 10 less than or equal to t less than or equal to 20 the change in temperature of the water in the system can be modeled by the equation S'(t)=-
\sqrt{2x} ( \frac{ {x}^{2}  - 100}}{x}
using this model determine the total change in the temperature of the system for the given interval. interpret your answer in the context of this problem​

Mathematics
2 answers:
Nana76 [90]3 years ago
7 0

Answer:

did anyone find it?

Step-by-step explanation:

GenaCL600 [577]3 years ago
3 0

Answer:

https://secure-media.collegeboard.org/apc/ap12_calculus_bc_q1.pdf

Step-by-step explanation:

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7x^2=9+x what are the values of x<br><br>Will give medal and points
DENIUS [597]
7x² = 9 + x   Subtract x from both sides
7x² - x = 9    Subtract 9 from both sides
7x² - x - 9 = 0   Use the Quadratic Formula

a = 7 , b = -1 , c = -9

x = \frac{-b \pm  \sqrt{b^2 - 4ac} }{2a}   Plug in the a, b, and c values
x = \frac{- (-1) \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Cancel out the double negative
x = \frac{1 \pm  \sqrt{(-1)^2 - 4(7)(-9)} }{2(7)}   Square -1
x = \frac{1 \pm  \sqrt{1 - 4(7)(-9)} }{2(7)}   Multiply 7 and -9
x = \frac{1 \pm  \sqrt{1 - 4(-63} }{2(7)}   Multiply -4 and -63
x = \frac{1 \pm  \sqrt{1 + 252} }{2(7)}   Multiply 2 and 7
x = \frac{1 \pm  \sqrt{1 + 252} }{14}   Add 1 and 252
x = \frac{1 \pm  \sqrt{253} }{14}   Split up the \pm
x = \left \{ {{ \frac{1 +  \sqrt{253} }{14} } \atop { \frac{1 -  \sqrt{253} }{14} }} \right.
The approximate square root of 253 is <span>15.905973.
</span>x ≈ \left \{ { \frac{1 + 15.905973}{14} } \atop { \frac{1 - 15.905973}{14} }} \right   Add and subtract
x ≈ \left \{ {{ \frac{16.905973}{14} } \atop { \frac{14.905973}{14} }} \right.   Divide
x ≈ \left \{ {{1.2075} \atop {1.0647}} \right.   Round to the nearest hundredth
x ≈ \left \{ {{1.21} \atop {1.06}} \right.

<span>
</span>
7 0
3 years ago
Find the value of h(-7) for the function below.
vovikov84 [41]

Answer:

  B.  138.7

Step-by-step explanation:

Put the given number where the variable is and do the arithmetic.

  h(x) = 5.7 -19x

  h(-7) = 5.7 -19(-7) = 5.7 +133 = 138.7

6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
Debora [2.8K]

Yo sup??

you can solve this quesion by having the knowledge of trigonometric ratios

let angle B be x, then

tanx=7/3

x=66.8

Hope this helps

4 0
3 years ago
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zavuch27 [327]
We are given with
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These are components of a geometric series. The first term is 2 and the common ratio is 4. To get the first six terms, we use the formula:
an = a1 r^(n-1)
a1 = 2 (4)^(1-1) = 2
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a4 = 2 (4)^(4-1) = 128
a5 = 2 (4)^(5-1) = 512
a6 = 2 (4)^(6-1) = 2048
8 0
3 years ago
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