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Galina-37 [17]
3 years ago
5

Four consecutive odd intergers whos sum is 56

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
4 0
Let N be the first of the four odd integers belonging to the sum. The next three integers are N+2, N+4, and N+6.

We then have

N+(N+2)+(N+4)+(N+6)=4N+12=56\implies 4N=44\implies N=11

and so the four integers are 11, 13, 15, and 17.
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