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3 years ago

Plz factor this completely

Mathematics

2 answers:

MrMuchimi3 years ago

3 0

What am I supposed to be factoring?

Stels [109]3 years ago

3 0

Answer:

(m + 2 - x) (m + 2 + x)

Step-by-step explanation:

m² + 4m + 4 - x²

m² + 2(m)(2) + 2² - x²

(m + 2)² - x²

(m + 2 - x) (m + 2 + x)

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Please solve quickly

Bumek [7]

Answer:

x=12

Step-by-step explanation:

AB/FE=BC/EC

x/6= 5+5/5

x/6=10/5

x=6(2)

x=12

6 0

2 years ago

20 POINTS

RUDIKE [14]

<em>The correct expressions are as follows:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

$\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }$

$\boxed { (a ^ b) ^ c = a ^ { b . c } }$

$\boxed {a ^ b \div a ^ c = a ^ { b - c } }$

$\boxed {\log a + \log b = \log (a \times b) }$

$\boxed {\log a - \log b = \log (a \div b) }$

<em>Let us tackle the problem!</em>

$\texttt{ }$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7^2)^{\frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5}} \cdot (7)^{2\times \frac{7}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{1}{5} + \frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{\frac{15}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = 7^{3}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}} = \boxed{343}$

$\texttt{ }$

<em>From the results above, it can be concluded that the correct statements are:</em>

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $343$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Equivalent $7^{\frac{1}{5}} \cdot 7^{\frac{14}{5}}$

$7^{\frac{1}{5}} \cdot 49^{\frac{7}{5}}$ Not Equivalent $49^{\frac{2}{10}} \cdot 7^{\frac{1}{5}}$

$\texttt{ }$

<h3>Learn more</h3>

Coefficient of A Square Root : brainly.com/question/11337634
The Order of Operations : brainly.com/question/10821615
Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

4 0

4 years ago

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In a random sample of students at a middle school 24 wanted to change the mascot and 30 wanted to keep the current mascot which

olasank [31]

In a random sample of students at a middle school 24 wanted to change the mascot and 30 wanted to keep the current mascot.

So total number of students in the sample = 30+24= 54

Number of students in random sample who wanted to keep the current mascot = 30

So out of 54 students 30 wanted to keep current mascot.

So for 1140 students = (30/54)*1140 = 633 students want to keep the currect mascot.

Answer: Third option 633 students.

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3 years ago

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Why do people hate math?

hichkok12 [17]

Answer: sometimes its really hard and other times its easy.

Step-by-step explanation: hope this helps!

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What is the additive inverse of the complex number –8 + 3i?<br><br> C on edg.

yawa3891 [41]

The answer is 8-3i on edge!

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