Years for one serious accident is 10 year
<u>Given:</u>
Probability of having a serious accident = 10% every year
P(serious accident) = 0.1
Number of years = n
<u>Computation:</u>
Years for one serious accident = 1 / Probability of having a serious accident
Years for one serious accident = 1 / P(serious accident)
Years for one serious accident = 1 / 0.1
Years for one serious accident = 10 year
Learn more:
brainly.com/question/23044118?referrer=searchResults
Answer:
I think its 1/6 and if I'm wrong I'm very sorry but I think its 1/6
Step-by-step explanation:
Answer:
X= 232÷ 2-40
Step-by-step explanation:
so first you minus the 40 giving you 192. The you do 192 ÷ 2 giving you 96$. So Trey had 96$ saved before mowing lawns.
Answer:
100,000 + 30,000 + 900 + 80 + 7
(Brainliest please! :D)
<h3><u><em>My friends the answer is:</em></u></h3><h3><u><em>If 1 lunch =$2.50
</em></u></h3><h3><u><em>
2 lunches = $5.00 (2.50x2)
</em></u></h3><h3><u><em>
3 lunches =$7.50
</em></u></h3><h3><u><em>
4 lunches =$10.00
</em></u></h3><h3><u><em>
5 lunches= $12.50
</em></u></h3><h3><u><em>
Just add $2.50</em></u></h3>
