Anybody please? Trying to figure this out don’t want to risk it

Which of the following is a series ? Check all that apply . 1/2 + 1/4 + 1/6 + 1/16 + 3.14159 B. 1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 20

Julli [10]

Answer:

A Series is always a periodic sum of terms, so only A and D will apply to that definition

(where A= 1/2 + 1/4 + 1/6 + 1/16 + 3.14159 and B=25 - 5 - 10 - 15 - - 125

3 0

3 years ago

What is the solution of the system?

Kryger [21]

Greetings!

Solve the System, using Elimination:
$\left \{ {{4x+2y=18} \atop {2x+3y=15}} \right.$

Multiply Equation #2 by 2:
$\left \{ {{4x+2y=18} \atop {2(2x+3y)=2(15)}} \right.$

$\left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.$

Eliminate variable x:
$-\frac{ \left \{ {{4x+2y=18} \atop {4x+6y=30}} \right.}{0x-4y=-12}$

$4y=-12$

Divide both sides by 4:
$\frac{4y}{4}= \frac{12}{4}$

$y=3$

Input this value into one of the Equations:
$4x+2y=18$

$4x+2(3)=18$

Simplify:
$4x+6=18$

$(4x+6)+(-6)=(18)+(-6)$

$4x=12$

Divide both sides by 4.
$\frac{4x}{4}= \frac{12}{4}$

$x=3$

The Solution to this System (The Point of Intersection):
$\boxed{(3,3)}$

I hope this helped!
-Benjamin

7 0

3 years ago

The daily production cost, C, for x units is

disa [49]

I think the correct equation is

c(x) = 200 - 7x + 0.345x^2.

Domain is the set of x-values (i.e. units produced) that are feasible. This is all the positive integer values + 0, in case that you only consider that can produce whole units.

Range is the set of possible results for c(x), i.e. possible costs.

You can derive this from the fact that c(x) is a parabole and you can draw it, for which you can find the vertex of the parabola, the roots, the y-intercept, the shape (it open upwards given that the cofficient of x^2 is positive). Also limit the costs to be positive.

You can substitute some values for x to help you, for example:

x y

0 200

1 200 -7 +0.345 = 193.345

2 200 - 14 + .345 (4) = 187.38

3 200 - 21 + .345(9) = 182.105

4 200 - 28 + .345(16) = 177.52

5 200 - 35 + 0.345(25) = 173.625

6 200 - 42 + 0.345(36) = 170.42

10 200 - 70 + 0.345(100) =164.5

11 200 - 77 + 0.345(121) = 164.745

The functions does not have real roots, then the costs never decrease to 0.

The function starts at c(x) = 200, decreases until the vertex, (x =10, c=164.5) and starts to increase.

Then the range goes to 164.5 to infinity, limited to the solutcion for x = positive integers.

4 0

3 years ago

The 5th term of linear sequence is 17

dedylja [7]

Answer:

397

Step-by-step explanation:

lets say there's an eqn which is y = mx + c, x is the term no. (5, 6 in the egs provided), y is the value corresponding to x (17, 21)

to find the 100th term sequence we need to find m and c. m is how much y changes when x increases by 1

in this case we can find m easily (m = 21-17 = 4)

now we have c left so just sub one of the egs given to what we have alrd found

17 = 4(5) + c

17 = 20 + c

c = - 3

so the eqn is y = 4x - 3, and we can solve for when x = 100

y = 4(100) - 3

y = 397

hope this isn't too confusing :^)

7 0

3 years ago

WILL GIVE BRAINLYEST!!!

Ainat [17]

False
If numbers differ by one order of magnitude, x is about ten times different in quantity than y. If values differ by two orders of magnitude, they differ by a factor of about 100. Two numbers of the same order of magnitude have roughly the same scale: the larger value is less than ten times the smaller value.

8 0

3 years ago