Using Lagrange multipliers, we have the Lagrangian

with partial derivatives (set equal to 0)




Substituting the first three equations into the fourth allows us to solve for

:

For each possible value of

, we get two corresponding critical points at

.
At these points, respectively, we get a maximum value of

and a minimum value of

.
3, 6, 9, 12, 15, 18, 21, 24, 27, 30.
Answer:
83.79 cm²
Step-by-step explanation:
(please refer to attached)
recall that the volume of a cone is given by
V = (1/3) π r² h
where
r = radius = given as 4 cm
h = height = given as 5 cm
assume π = 3.142
substituting the values into the formula:
V = (1/3) π r² h
V = (1/3) (3.14) (4)² (5)
V = 83.79 cm²
Answer:
The right answer is: 14,256 cubic inches
Step-by-step explanation:
First of all, let's identify the dimensions of the tank and convert them to inches
Knowing that 1 Feet = 12 inches
So, the dimensions of the tank, expresed in inches will be:
Height (H): 2 ft. x 12 = 24 inches
Width (W): 1.50 ft. x 12 = 18 inches
Lenght (L): 3 ft. x 12 = 36 inches
Before calculating the volume of water inside the thank, We must consider that <em>there are two inches of empty space at the top.</em>
So , We must substract 2 inches to the height to calculate the volume.
Then, the height used for calculating the volume will be:
H'= 24 inches - 2 inches = 22 inches
Then,
Volume (V)= W x L x H'
V= (18 inches) x (36 inches) x (22 inches)
V= 14,256 cubic inches
Answer:
yoo
Step-by-step explanation: