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Aneli [31]
3 years ago
7

The base of a pyramid is a rectangle with a width of 4.6 cm and a length of 9 cm. What is the height, in centimeters, of the pyr

amid if its volume is 82.8 cubic cm?
A. 6 cm
B. 2 cm
C. 9 cm
D. 18 cm
Mathematics
1 answer:
Sauron [17]3 years ago
5 0

<u>Given</u>:

Given that the base of a pyramid is a rectangle with a width of 4.6 cm and a length of 9 cm.

The volume of the pyramid is 82.8 cubic cm.

We need to determine the height of the pyramid.

<u>Height of the pyramid:</u>

The height of the pyramid can be determined using the formula,

V=\frac{lwh}{3}

Substituting the values, we get;

82.8=\frac{9\times 4.6 \times h}{3}

Multiplying both sides by 3, we get;

248.4=41.4 \times h

Dividing both sides by 41.4, we have;

6=h

Thus, the height of the rectangular pyramid is 6 cm.

Hence, Option A is the correct answer.

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Re-arranging the numbers;
13.0, 13.5, 13.6, 14.1, 14.8, 15.8, 19.1, 21.6, 26.0, 30.8

Mean, x_bar = (13.0+13.5+13.6+14.1+14.8+15.8+19.1+21.6+26.0+30.8)/10 = 18.23

Standard deviation, sigma = Sqrt [{(13-18.23)^2+(13.5-18.23)^2+(13.6-18.23)^2+(14.1-18.23)^2+(14.8-18.23)^2+(15.8-18.23)^2+(19.1-18.23)^2+(21.6-18.23)^2+(26-18.23)^2+(30.8-18.23)^2}/10] = Sqrt [{27.3529+22.3729+21.4369+17.0569+11.7649+5.9049+0.7569+11.3569+60.3729+158.0049}/10] = Sqrt [336.381/10] = 5.8

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Confidence interval = x_bar +/- Z*sigma/Sqrt (n) = 18.23+/- 2.58*5.8/Sqrt (10) = 18.23+/-4.73 = [(18.23-4.73), (18.23+4.73)] = [13.5,22.96]
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