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Semenov [28]
4 years ago
11

How do i solve x/2+1/3=x/3+1/2

Mathematics
2 answers:
stepladder [879]4 years ago
8 0
X/2+1/3=x/3+1/2
x/2=x/3+1/2-1/3
x/2 - x/3 = 3/6 - 2/6
x/2 - x/3 = 1/6
3x/6 - 2x/6 = 1/6
x/6 = 1/6
x = 1/6 * 6

x = 1

laila [671]4 years ago
3 0
\frac{1}{2}x + \frac{1}{3} = \frac{1}{3}x + \frac{1}{2} \\\frac{1}{6}x + \frac{1}{3} = \frac{1}{2} \\\frac{1}{6}x = \frac{1}{6} \\6(\frac{1}{6}x)  = 6(\frac{1}{6}) \\x = 1
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7 0
3 years ago
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(10.04 MC)
Luba_88 [7]

Answer:

f

(

x

)

=

3

cos

(

2

x

)

+

2

EXPLANATION:

We are able to use the transformation formula

f

(

x

)

=

a

⋅

cos

(

x

−

h

b

)

+

k

. You start with

f

(

x

)

=

cos

(

x

)

and replace

a

with the desired amplitude,

h

with the desired horizontal shift, and

k

with the desired vertical shift. This leaves out the

b

-value. A regular cosine function has a period of

2

π

. If you want a period of

π

, since that is one half of the original period, you need to replace your

b

with a

1

2

.

This is about how it would work out.

f

(

x

)

=

3

⋅

cos

(

x

−

0

1

2

)

+

2

From there you simplify your equation giving you

f

(

x

)

=

3

cos

(

2

x

)

+

2

4 0
3 years ago
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