Answer:
b=44
b=44 - 9
b=44 + 5
x+x+x = 44
x + (x-9) + (x+5) = 44
3x - 4 = 44
+4
3x =48
÷3
x=16
So, first photo contains 16 birds.
x=16
(x-9) - - > 16-9 = 7
(x+5) - - >16+5=21
16 + 7 + 21 =44
Answer is 16 birds in first photo
Hope this helps!
Answer:
x = -7 2/3, y = 1 1/3 and z = 5 1/3.
Step-by-step explanation:
2x+4y+3z=6 ..... 1
x-2y+z=-5 ...... 2
-x-3y-2z=-7 .......3
Add equations 2 and 3 to eliminate x:
-5y - z = -12 .....4
Multiply equation 2 by - 2:
-2x + 4y - 2z = 10
Add this to equation 1:
8y + z = 16 ........ 5
Now add equation 4 to equation 5:
3y = 4
y = 4/3 = 1 1/3.
Now find z by substituting for y in equation 4:
-5(4/3) - z = -12
z = 12 - 20/3
z = 36/3 - 20/3 = 16/3 = 5 1/3.
Finally, we find x by substituting for y and z in equation 1:
2x + 4*4/3 + 3*16/3 = 6
2x = 6 - 16/3 - 16
2x = 18/3 - 16/3 - 48/3 = -46/3
x = 23/3 = 7 2/3.
Step-by-step explanation:
k² + 5k + 13 = 0
Using the quadratic formula which is

From the question
a = 1 , b = 5 , c = 13
So we have

<u>Separate the solutions</u>

The equation has complex roots
<u>Separate the real and imaginary parts</u>
We have the final answer as

Hope this helps you
Answer:
The class width is 20
Step-by-step explanation:
In a frequency or a relative frequency distribution the class width is calculated as the difference between the lower or upper class limits of consecutive classes. A point to note is that all the categories or classes usually have the same class width.
We use the first two classes to calculate the class width by using their respective upper limits;
Class width = 89 - 69
Class width = 20
The answer to the question is 11/14