Answer: 1/5, 1/2, 0.
Step-by-step explanation:
given data:
no of cameras = 6
no of cameras defective = 3
no of cameras selected = 2
Let p(t):=P(X=t)
p(2)=m/n,
m=binomial(3,2)=3!/2!= 3
n=binomial(6,2)=6!/2!/4! = 15
p(3)= 3/15
= 1/5.
p(1)=m/n,
m=binomial(6,1)*binomial(2,2)=6!/1!/4!*2!/2!/0!= 7.5
n=binomial(6,2)= 15
p(2)= 7.5/15
= 1/2
p(0)=m/n,
m=0
p(0)=0
The locations specified in the order regarding the shape will be B. longest side AC; smallest angle ∠C.
<h3>How to express the information?</h3>
From the information given, in the triangle where A = 59°, B is unknown, and C = 41°. Therefore, the value of B will be:
= 180° - (59° + 41°)
= 180° - 100°
= 80°
Therefore, the locations specified in the order regarding the shape will be longest side AC; smallest angle ∠C.
In conclusion, the correct option is B.
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Answer:
The answer is (g°f)(-1) = 27
Step-by-step explanation:
* (g°f)(1) ⇒ means make the domain of g is the range of f
- At first find the value of f(-1)
- Take the answer and substitute it as the value of x for g
- So the range of f is the domain of g
∵ f(x) = 4x + 7
∵ The domain of f = -1 ⇒ x is the domain
∴ f(-1) = 4(-1) + 7 = -4 + 7 = 3 ⇒ f(-1) is the range
∵ g(x) = x³
∵ x = f(-1) = 3 ⇒ the domain of g
∴ g(3) = 3³ = 27 ⇒ the range of g
* (g°f)(-1) = 27