Answer:
Step-by-step explanation:
I assume your equation to solve is
When we have a product of two factors equal to zero,
The solution is either A = 0 or B = 0.
In this case, this means that we can break the equation into two equations:
Solving the first one, we get:
For the second one, we rewrite it as:
And we see that this equation has two solutions:
Therefore, the three solutions are:
Answer:
<h3>25m</h3>
Step-by-step explanation:
Perimeter of the rectangular pasture P = 2(L+W)
Area A = LW
L is the length
W is the width
Given
Perimeter = 110m
Area = 750m
If the length of the pasture is 40m longer than the width, then L = W+40
110 = 2L+2w
55 = L+W .....1
750 = LW.....2
Solving simultaneously
from 1; L = 55-W
substitute into 2;
750 = (55-W)W
750 = 55W-W²
-W²+55W -750 = 0
W²-55W+750 = 0
(W²-25W)-(30W+750) = 0
W(W-25)-30(W-25) = 0
(W-25)(W-30) = 0
W-25 = 0 and W-30 = 0
w = 25m and 30m
Since L = 55-W
L = 55-25 = 30m and;
L = 55-30 = 25m
Since we are told that length id longer than the width then, the width we are going to use is 25m
The Pythagorean Theorem states that the sum of the squares of the lengths of the legs of a right triangle is equal to the square of the length of the hypotenuse. Use the Pythagorean Theorem formula
+ (14 Ft.) = (13Ft.)
+ (13)(13) = (14)(14)
+ 169 = 196
= 196-169
= 27
<span><span>5<span><span>(<span>14−2</span>)^</span>2/</span></span>2
</span><span>=<span><span>5<span>(<span>12^2</span>)/</span></span>2</span></span><span>=
<span><span><span>(5)</span><span>(144)/</span></span>2
</span></span><span>=<span>720/2</span></span><span>=
<span>360</span></span>