9514 1404 393
Answer:
64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Step-by-step explanation:
The row of Pascal's triangle we need for a 6th power expansion is ...
1, 6, 15, 20, 15, 6, 1
These are the coefficients of the products (a^(n-k))(b^k) in the expansion of (a+b)^n as k ranges from 0 to n.
Your expansion is ...
1(2k)^6(-1/3)^0 +6(2k)^5(-1/3)^1 +15(2k)^4(-1/3)^2 +20(2k)^3(-1/3)^3 +...
15(2k)^2(-1/3)^4 +6(2k)^1(-1/3)^5 +1(2k)^0(-1/3)^6
= 64k^6 -64k^5 +(80/3)k^4 -(160/27)k^3 +(20/27)k^2 -(4/81)k +1/729
Answer:
djchdjcycuchrivivurtiytvivytivi8fr cgdyhcd8w
![\sqrt[3]{x + 1} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%20%3D%202)
Let us cube both sides.
![= > (\sqrt[3]{x + 1} ) ^{3} = {2}^{3}](https://tex.z-dn.net/?f=%20%3D%20%20%3E%20%20%28%5Csqrt%5B3%5D%7Bx%20%2B%201%7D%20%29%20%5E%7B3%7D%20%20%3D%20%20%7B2%7D%5E%7B3%7D%20)
Now, it will be only x + 1.
Transpose 1 to the Right Hand Side.
Now, subtract.
<u>Answer</u><u>:</u>
x = 7
Hope you could understand.
If you have any query, feel free to ask.
Answer:
-6
Step-by-step explanation:
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