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IRINA_888 [86]
3 years ago
14

Mountain View Middle School students work on square desktops. The area of the square desk surface is 4 square feet. What is the

length of each side of the desktop?
Mathematics
1 answer:
ahrayia [7]3 years ago
8 0

Answer:

2 Feet

Step-by-step explanation:

The area is found by multiplying length by width. Since its a square the length and width are the same and it would have to be 2.

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The subtraction property of equality states that the two sides of an
yawa3891 [41]

Answer:

False

Step-by-step explanation:

The answer is in its name. Its a property of equality meaning it makes sure that both sides are equal to each other

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1 year ago
Please help asap 20 pts
My name is Ann [436]
C because 5 is (5,0)
8 0
3 years ago
Pls help im doing math and in terriable..
8_murik_8 [283]

Answer:

64 points/80 points

80/100

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Approximate: log5 4/7
Evgesh-ka [11]
   Properties of Logs

logb(x/y) = log<span>bx</span> - log<span>by</span>.

therefore

log5 (4/7)= log5 (4)- log5 (7)

<span>Solve log 5 (4) and log 5 (7)  with the base change of the logarithm</span>

<span>log 5 4 = log 4 / log 5 </span>

 Use the calculator: 

<span> <span>log 5 4 =0.8613531161 </span></span>

 log 5 7 = log 7 / log 5 

<span>log 5 7 =1.2090619551</span>

<span>log5 (4/7)= log5 (4)- log5 (7)=-0.347708839</span>

6 0
3 years ago
Read 2 more answers
A committee of 5 people is to be chosen from a group of 8 women and 10 men. How many diffferent committees are possible? How man
Jet001 [13]
A) 5 to be chosen among a Total : 10 Men + 8 Women

¹⁸C₅ = (18!)/(5!)(13!) = 8,568 groups of five

b) A must to have men and women. If so we have to deduct all groups of 5 that are all men and all group of 5 that are all women
Groups of 5 with only men: ¹⁰C₅ = 252
Groups of 5 with only women: ⁸C₅ = 56

So number of committees of 5 men and women mixed =
8568 - 252 - 56 = 8,260 committees 

c) 3 Women and 2 Men:

⁸C₃ x ¹⁰C₂ = 2,520 groups of 3 W and 2 M

d) More women than men, it means:
  3 W + 2 M OR (we have found it in c) = 2,520)
  4 W + 1 M OR   ⁸C₄ x ¹⁰C₁   →→→→ =    700
  5 W + 0 M OR   ⁸C₅ x ¹⁰C₀   →→→→  =     56

Total where W>M = 3,276 groups of 5 where women are at least 3


3 0
3 years ago
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