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den301095 [7]
3 years ago
12

Here is the real two

Mathematics
2 answers:
Talja [164]3 years ago
5 0
A is the answer for the first and the second one is 1/3.HERE ARE URE ANSWERS
Rudiy273 years ago
4 0
The answer to the graph is D 1/3
The answer to the simplify one is C
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Identify the function as a growth or decay function. y = (1/2)x
tangare [24]

Answer:

This would be a decay function.

Step-by-step explanation:

When a function is a growth function that means that it is growing but a decay function means that it is getting smaller.

8 0
3 years ago
Planes X and Y are perpendicular. Points A, E, F, and G are points only in plane X. Points R and S are points in both planes X a
NemiM [27]
Given:

Planes X and Y are perpendicular to each other
Points A, E, F, and G are points only in plane X
Points R and S are points in both planes X and Y
Lines EA and FG are parallel

The lines which could be perpendicular to RS are EA and FG. 
6 0
3 years ago
Read 2 more answers
PLEASE HELP MEEEE HURRRY!!! :)
sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}  First, I swapped the first and third rows.

\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}  Leading coefficient of row 2 canceled.  

\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}  The start value of row 3 was canceled.

\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}       Matrix rows 2 and 3 were swapped.

\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}      Leading coefficient in row 3 was canceled.

\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

6 0
3 years ago
Tara pays $20.50 for 8.2 pounds of potatoes. What is the price per pound of potatoes?
Masteriza [31]

Answer:

She pays $2.5 per pound

Step-by-step explanation:

8 0
3 years ago
Can someone please answer all of the questions?
In-s [12.5K]
6F 7T 8F 9F there :D
7 0
3 years ago
Read 2 more answers
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