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Cloud [144]
3 years ago
15

What system of inequalities would you use to solve the problem below

Mathematics
1 answer:
Fudgin [204]3 years ago
5 0
What problem is being shown ?
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Given that an intercepted arc has length 6pi inches and a central angle is pi/3, find the radius
MA_775_DIABLO [31]
\bf \textit{arc's length}\\\\
s=r\theta \quad 
\begin{cases}
r=radius\\
\theta =angle~in\\
\qquad radians\\
------\\
s=6\pi \\
\theta =\frac{\pi }{3}
\end{cases}\implies 6\pi =r\left( \frac{\pi }{3} \right)\implies \cfrac{6\pi }{\frac{\pi }{3}}=r
\\\\\\
\cfrac{6\pi }{1}\cdot \cfrac{3}{\pi }=r\implies 18=r
5 0
4 years ago
Triangle P=27,Q=40,P=33 law of sines round measures to the nearest tenth
nordsb [41]
For the law of sines, you would apply it in this particular problem like so:
Since P is 27, its angle is 33 and Q's length is 40; you would set it up like this
<u />40/SinQ = 27/Sin33, multiply 40 with Sin33, then it would be 40Sin33, then divide it by 27. The result should be 40Sin33/27 = X

5 0
3 years ago
Find the sum (a-b)(2a+4b)
Mama L [17]
(a-b)(2a+4b) = 2a² - 2ab + 4ab - 4b² =  2a² + 2ab - 4b²
7 0
3 years ago
No answer text provided.
zheka24 [161]

Answer:

HM > CH

Step-by-step explanation:

You are correct, I didn't see the option HM > CH, which is correct, since the angle 90 degrees is larger than the angle 73, and then the sides opposite to them must follow suit.

Therefore, the correct answer is: HM > CH

5 0
3 years ago
Read 2 more answers
Pls help!!!!!!!!!!!!
nikklg [1K]
The measure of angle R is 50° because x=3.
7 0
3 years ago
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