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3 years ago

I need help fast I’ll really appreciate it.

Mathematics

2 answers:

fgiga [73]3 years ago

6 0

Answer:

11 : 8

Step-by-step explanation:

3 + 8 = 11

emmainna [20.7K]3 years ago

6 0

Answer:

11:8

Step-by-step explanation:

I think i may be wrong I hope this is right

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What subtraction sentence does this show?

harina [27]

Ummmmmmmmmmmmm
Mm A is correct I think. The question was unclear but A is the only correct function

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2 years ago

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quester [9]

Answer:

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3 years ago

Translate the statement below. "One less than twice a number.."

Inga [223]

One less than twice a number is seventeen.

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3 years ago

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Question 29: In a club of 35 boys and 28 girls, 80% of the boys and 25% of the girls have been members for more than 2 years. If

klasskru [66]

Answer:

55%

Step-by-step explanation:

What we must do is get the total number of people, that is, boys and girls who have been a member for more than 2 years, that is:

children: 0.8 * 35 = 28

girls = 0.25 * 28 = 7

Now, passing knowing the%, would be dividing the sum of the above by the sum of the total club members:

(28 +7) / (35 + 28) = 0.55

Since it is a number below 1, it cannot be a mixed number.

3 0

3 years ago

Read 2 more answers

Factorise 2x^2 - 3x -2 < 0

Galina-37 [17]

Step 1: Factor $2 x^{2} - 3x -2$
1. Multiply 2 by -2, which is -4.
2. Ask: Which two numbers add up to -3 and multiply to -4?
3. Answer: 1 and -4
4. Rewrite $-3x$ as the sum of $x$ and $-4x$

$2 x^{2} +x-4x-2\ \textless \ 0$

Step 2: Factor out common terms in the first two terms, then in the last two terms.

 $x(2x+1)-2(2x+1)\ \textless \ 0$

Step 3: Factor out the common term $2x+1$

$(2x+1)(x-2)\ \textless \ 0$

Step 4: Solve for $x$

1. Ask: When will $(2x+1)(x-2)$ equal zero?
2. Answer: When $2x + 1 = 0$ or $x-2=0$
3. Solve each of the 2 equations above:

 $x=- \frac{1}{2} ,2$

Step 5: From the values of $x$ above, we have these 3 intervals to test.
x = < -1/2
-1/2 < x < 2
x > 2

Step 6: Pick a test point for each interval

For the interval $x\ \textless \ - \frac{1}{2} 
$
Lets pick $x=-1.$ Then, $2(-1) ^{2} -3 * -1 -2 \ \textless \ 0$
After simplifying, we get $3\ \textless \ 0$ , Which is false.
Drop this interval.

For this interval $- \frac{1}{2} \ \textless \ x\ \textless \ 2$
Lets pick $x=0$ . Then, $2* 0^{2} - 3 * 0-2\ \textless \ 0$ . After simplifying, we get $-2\ \textless \ 0,$ which is true. Keep this interval.

For the interval $x\ \textgreater \ 2$

Lets pick $x = 3.$ Then, $2 * 3 ^{2} -3*3-2\ \textless \ 0.$ After simplifying, we get $7\ \textless \ 0$ , Which is false. Drop this interval.

.Step 7: Therefore,
$- \frac{1}{2} \ \textless \ x\ \textless \ 2$

Done! :)

4 0

4 years ago