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Stella [2.4K]
3 years ago
13

An electronic store sells a large flat screen television for $1,699. Last month, the store sold 8 of these television sets. Abou

t how much money did the televisions sell for?
Mathematics
2 answers:
serg [7]3 years ago
6 0
1699 / 8 = 212.375 and then round $212.38 per TV
Maurinko [17]3 years ago
6 0
$212 dollors just divide 1,699 with 8
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B. 11.33 is closer to the area of a circle with a radius of 2.1
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Answer:

hope this helps.. look at it this way it should help!!

Step-by-step explanation:

Considered as an ideal camping axe, the Boy’s Axe (also called the ¾ Axe) usually has a length of 28 inches, ¾ of 36 inches being 27 inches or roughly 700 millimeters. Finally, the Scout Axe has an average handle length of 18-20 inches or 450-500 millimeters.

6 0
3 years ago
Create an equation that represents a parabola that opens upward
algol13

For a parabola that opens upward, it must be a quadratic equation whose coefficient of x2 is a positive number.

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3 years ago
A hollow metal sphere has 6 cm inner and 8cm outer radii. The surface charge densities on the exterior surface is +100 nC/m2 and
natulia [17]

Answer:

<h2>Outer Electric Field is 11250 N/C.</h2><h2>Inner Electric Field is -10000 N/C.</h2>

Step-by-step explanation:

First of all, we need to read carefully and analyse the problem. As you can see, is an electrical subject, and it's given surface charge densities and radius.

So, to calculate electric fields, we need to find the proper equation to do so: E=k\frac{q}{r^{2} }; as you can see, first we need to find the charges.

We can find all charges using the surface charge densities, because it has the next relation: p=\frac{q}{A}; which indicates that charge density is the amount of charge per area. But, there's a problem, we don't have areas, so we have to calculate them first with this relation: S=4\pi r^{2}; which gives us the surface of a sphere.

The inner surface: Si=4\pi (0.06m)^{2} = 0.04 m^{2}

The outer surface: S=4\pi (0.08m)^{2}=0.08m^{2}

Now we can calculate the charges,

Inner charge: Qi=pA=(-100\frac{nC}{m^{2} } )(0.04m^{2} )=-4nC

Outer charge: Qo=pA=100\frac{nC}{m^{2} } )(0.08m^{2} )=8nC

Then, we are able to calculate both fields:

Inner field: Ei=k\frac{Qi}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{-4x10^{-9} }{0.06m^{2} }=-10000\frac{N}{C}

Outer field:  Eo=k\frac{Qo}{r^{2} }=9x10^{9} \frac{Nm^{2} }{C^{2} }\frac{8x10^{-9} }{0.08m^{2} }=11250\frac{N}{C}

The directions that field have is opposite each other, the inner one has an inside direction, and the outer electric field has an outside direction.

3 0
3 years ago
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Svet_ta [14]

Answer:      -2.5,, -0.9,, -1/3,, 1.7,, 27/4

Step-by-step explanation:

6 0
3 years ago
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