All categories

3 years ago

Describe the pattern in the numbers. Write the next number in the pattern. 1, 2/3, 1/3, 0

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

Answer:

-1/3

Step-by-step explanation:

its subtracting 1/3 every time

You might be interested in

How can I find a? (Trigonometric Ratios)

earnstyle [38]

Step-by-step explanation:

Hey there!

Use cos ratio to find the value of 'a'.

As per given, we can state that it is a Right angled triangle, so taking 38° reference angle.

We get;

p = AC

b = 6

and h= a

Here, Use the value of b, h and 38° angle to find the value of a.

$\cos(38° ) = \frac{b}{h}$

$\cos(38°) = \frac{6}{a}$

$0.7881 = \frac{6}{a}$ [ cos(38°=0.7881]

$0.7881a = 6$

$a = \frac{6}{0.7881}$

Therefore the measure of a is 7.61 Or 8.

Hope it helps..

6 0

3 years ago

Can anyone help please?

Korolek [52]

Answer:

Step-by-step explanation:

6(2) = 12

12 + 9 = 21

21/3 = 7

7 - 1 = 6 <--- Number that's she's thinking

I tested every number!

8 0

2 years ago

Read 2 more answers

The town of Fitzgerald wants to build a coffee house halfway between Oak Station and Pine Station. Where should it be located (l

Lubov Fominskaja [6]

Answer:

1, 1/2

Step-by-step explanation:

the coordinates would be Oak station(8,8) and Pine Station(-6,-7).

The midpoints would be

=[8+(-6)]/2 , [8+(-7)]/2

=2/2 , 1/2

=1, 1/2

4 0

3 years ago

WIll MARK BRAINLIEST IF ANSWER IN 2 MINUTES!!!! Which represents the equation 6 x + 3 y = 12 when solved for y? y = negative 2 x

KiRa [710]

Answer:

y=-2x+4

Step-by-step explanation:

6x+3y=12

3y=-6x+12

y=-2x+4

3 0

3 years ago

Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.

3 0

3 years ago