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MariettaO [177]
3 years ago
11

What is the sum of an infinite geometric series if a1 = 144 and r = 1⁄4?

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
7 0

Answer:

D

Step-by-step explanation:

The sum to infinity of a geometric sequence is

sum to infinity = \frac{a_{1} }{1-r}

here a_{1} = 144 and r = \frac{1}{4}, hence

sum = \frac{144}{1-\frac{1}{4} }

      = \frac{144}{\frac{3}{4} }

      = \frac{144(4)}{3} = 192 → D

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Solve: x=4+(4x-4)1/2
Damm [24]

Answer:

x = 10

Step-by-step explanation:

x = 4 + (4x-4) ^ (1/2)

First, we rewrite the expression:

x = 4 + (4x-4) ^ (1/2)

x = 2 (2+ (x-1) ^ (1/2))

x = 4 + 2 (x-1) ^ (1/2)

From here we get a solution for x = 10

To check it we substitute x = 10 in the expression:

10 = 4 + 2 (10-1) ^ (1/2)

10 = 4 + 2 (9) ^ (1/2)

10 = 4 + 2 (3)

10 = 4 + 6

10 = 10

Answer:

The solution is:

x = 10

8 0
3 years ago
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natka813 [3]

Answer:

D and C

Step-by-step explanation:

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Leena has 2/3 of a glass of milk with her. She gives 1/6 of it to her cat. How much of milk is left with her now?
Dmitrij [34]

Answer:

1/2 glass milk is left.

Step-by-step explanation:

2/3 - 1/6 = 1/2

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3 years ago
David played a slot machine. W(t) models his winnings (in dollars, where a negative number means David is losing) as a function
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Step-by-step explanation:

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3 years ago
Please helpp middle school math<br><br>suppose 4&lt;a&lt;7. find all the possible values of 15-2a​
bixtya [17]

9514 1404 393

Answer:

  1 < 15 -2a < 7

Step-by-step explanation:

There are a couple of ways you can do this.

1) Put the minimum and maximum values of a into the expression to see what its corresponding values are:

  15-2a for a=4:

     15-2(4) = 7

  15-2a for a=7:

     15-2(7) = 1

Then ...

  1 < 15-2a < 7

__

2) Solve for a in terms of the value of 15-2a, then impose the limits on a.

  x = 15 -2a

  2a = 15 -x

  a = (15 -x)/2

Now, impose the given limits:

  4 < (15 -x)/2 < 7

  8 < 15 -x < 14 . . . multiply by 2

  -7 < -x < -1 . . . . . . subtract 15

  7 > x > 1 . . . . . . . . multiply by -1

  1 < 15-2a < 7 . . . . . use x=15-2a

_____

The vertical extent of the attached graph is the range of possible values of 15-2a. It goes from 1 to 7.

8 0
3 years ago
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