Answer:
let
tp=total points lost
l= points lost
q= question
tp=24
l= 3
if l= 3 and tp= 24 den q= tp÷l
24÷3=8
6? maybe 12 idk but its the best i could do
Answer:
44
Step-by-step explanation:
First you have to make sure that you move everything from one side to the other and set the equation equal to zero. Then you have to simplify the equation as much as you can so you get:
x/14
7 * (x/14)
eventually you get
(x-22)/2 =0
from there you can solve for 44
Answer:
0.36 ( hope this helps :)
Explanation:
There may be a more direct way to do this, but here's one way. We make no claim that the statements used here are on your menu of statements.
<u>Statement</u> . . . . <u>Reason</u>
2. ∆ADB, ∆ACB are isosceles . . . . definition of isosceles triangle
3. AD ≅ BD
and ∠CAE ≅ ∠CBE . . . . definition of isosceles triangle
4. ∠CAE = ∠CAD +∠DAE
and ∠CBE = ∠CBD +∠DBE . . . . angle addition postulate
5. ∠CAD +∠DAE ≅ ∠CBD +∠DBE . . . . substitution property of equality
6. ∠CAD +∠DAE ≅ ∠CBD +∠DAE . . . . substitution property of equality
7. ∠CAD ≅ ∠CBD . . . . subtraction property of equality
8. ∆CAD ≅ ∆CBD . . . . SAS congruence postulate
9. ∠ACD ≅ ∠BCD . . . . CPCTC
10. DC bisects ∠ACB . . . . definition of angle bisector