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nalin [4]
3 years ago
6

Solutions to these equations??

Mathematics
2 answers:
madam [21]3 years ago
5 0
1)x= +3, -3
2)x= +8, -8
3)x= 2
Akimi4 [234]3 years ago
3 0
X = 4.5
x^2=64, X = 7
x=2
You might be interested in
Marta wants to purchase charms for her necklace. Each charm cost $1.59. She wants to spend no more than $20 for the charms. Whic
Svetllana [295]

Which inequality represents this situation ?

1.59×n < 20

How many charms can Marta purchase ?

20 : 1.59 = 12 (+$0.92)

5 0
3 years ago
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

8 0
3 years ago
Approximate the square root to the nearest whole number 142
slamgirl [31]
The square root of 142 is 11.916
7 0
2 years ago
Help please i will mark brainlyy
skelet666 [1.2K]

Answer:

x =(-4+√88)/12=-1/3+1/6√ 22 = 0.448

x =(-4-√88)/12=-1/3-1/6√ 22 = -1.115

Step-by-step explanation:

x =(-4-√88)/12=-1/3-1/6√ 22 = -1.115

x =(-4+√88)/12=-1/3+1/6√ 22 = 0.448

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((2•3x2) +  4x) -  3  = 0  

Step  2  :

Trying to factor by splitting the middle term

2.1     Factoring  6x2+4x-3  

The first term is,  6x2  its coefficient is  6 .

The middle term is,  +4x  its coefficient is  4 .

The last term, "the constant", is  -3  

Step-1 : Multiply the coefficient of the first term by the constant   6 • -3 = -18  

Step-2 : Find two factors of  -18  whose sum equals the coefficient of the middle term, which is   4 .

     -18    +    1    =    -17  

     -9    +    2    =    -7  

     -6    +    3    =    -3  

     -3    +    6    =    3  

     -2    +    9    =    7  

     -1    +    18    =    17  

Observation : No two such factors can be found !!

Conclusion : Trinomial can not be factored

Equation at the end of step  2  :

 6x2 + 4x - 3  = 0  

Step  3  :

Parabola, Finding the Vertex :

3.1      Find the Vertex of   y = 6x2+4x-3

Parabolas have a highest or a lowest point called the Vertex .   Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) .   We know this even before plotting  "y"  because the coefficient of the first term, 6 , is positive (greater than zero).  

Each parabola has a vertical line of symmetry that passes through its vertex. Because of this symmetry, the line of symmetry would, for example, pass through the midpoint of the two  x -intercepts (roots or solutions) of the parabola. That is, if the parabola has indeed two real solutions.  

Parabolas can model many real life situations, such as the height above ground, of an object thrown upward, after some period of time. The vertex of the parabola can provide us with information, such as the maximum height that object, thrown upwards, can reach. For this reason we want to be able to find the coordinates of the vertex.  

For any parabola,Ax2+Bx+C,the  x -coordinate of the vertex is given by  -B/(2A) . In our case the  x  coordinate is  -0.3333  

Plugging into the parabola formula  -0.3333  for  x  we can calculate the  y -coordinate :  

 y = 6.0 * -0.33 * -0.33 + 4.0 * -0.33 - 3.0

or   y = -3.667

Parabola, Graphing Vertex and X-Intercepts :

Root plot for :  y = 6x2+4x-3

Axis of Symmetry (dashed)  {x}={-0.33}  

Vertex at  {x,y} = {-0.33,-3.67}  

x -Intercepts (Roots) :

Root 1 at  {x,y} = {-1.12, 0.00}  

Root 2 at  {x,y} = { 0.45, 0.00}  

Solve Quadratic Equation by Completing The Square

3.2     Solving   6x2+4x-3 = 0 by Completing The Square .

Divide both sides of the equation by  6  to have 1 as the coefficient of the first term :

  x2+(2/3)x-(1/2) = 0

Add  1/2  to both side of the equation :

  x2+(2/3)x = 1/2

Now the clever bit: Take the coefficient of  x , which is  2/3 , divide by two, giving  1/3 , and finally square it giving  1/9  

Add  1/9  to both sides of the equation :

 On the right hand side we have :

  1/2  +  1/9   The common denominator of the two fractions is  18   Adding  (9/18)+(2/18)  gives  11/18  

 So adding to both sides we finally get :

  x2+(2/3)x+(1/9) = 11/18

Adding  1/9  has completed the left hand side into a perfect square :

  x2+(2/3)x+(1/9)  =

  (x+(1/3)) • (x+(1/3))  =

 (x+(1/3))2

Things which are equal to the same thing are also equal to one another. Since

  x2+(2/3)x+(1/9) = 11/18 and

  x2+(2/3)x+(1/9) = (x+(1/3))2

then, according to the law of transitivity,

  (x+(1/3))2 = 11/18

We'll refer to this Equation as  Eq. #3.2.1  

The Square Root Principle says that When two things are equal, their square roots are equal.

Note that the square root of

  (x+(1/3))2   is

  (x+(1/3))2/2 =

 (x+(1/3))1 =

  x+(1/3)

Now, applying the Square Root Principle to  Eq. #3.2.1  we get:

  x+(1/3) = √ 11/18

Subtract  1/3  from both sides to obtain:

  x = -1/3 + √ 11/18

Since a square root has two values, one positive and the other negative

  x2 + (2/3)x - (1/2) = 0

  has two solutions:

 x = -1/3 + √ 11/18

  or

 x = -1/3 - √ 11/18

Note that  √ 11/18 can be written as

 √ 11  / √ 18  

Solve Quadratic Equation using the Quadratic Formula

3.3     Solving    6x2+4x-3 = 0 by the Quadratic Formula .

According to the Quadratic Formula,  x  , the solution for   Ax2+Bx+C  = 0  , where  A, B  and  C  are numbers, often called coefficients, is given by :

                                     

           - B  ±  √ B2-4AC

 x =   ————————

                     2A

 In our case,  A   =     6

                     B   =    4

                     C   =   -3

Accordingly,  B2  -  4AC   =

                    16 - (-72) =

                    88

Applying the quadratic formula :

              -4 ± √ 88

  x  =    —————

                   12

Can  √ 88 be simplified ?

Yes!   The prime factorization of  88   is

  2•2•2•11  

To be able to remove something from under the radical, there have to be  2  instances of it (because we are taking a square i.e. second root).

√ 88   =  √ 2•2•2•11   =

               ±  2 • √ 22

 √ 22   , rounded to 4 decimal digits, is   4.6904

So now we are looking at:

          x  =  ( -4 ± 2 •  4.690 ) / 12

Two real solutions:

x =(-4+√88)/12=-1/3+1/6√ 22 = 0.448

or:

x =(-4-√88)/12=-1/3-1/6√ 22 = -1.115

5 0
3 years ago
Read 2 more answers
What's the perimeter or how do you find it?
ziro4ka [17]

The perimeter of inside of the track is 536.44m

<h3>Perimeter of a circle and rectangle</h3>

The perimeter of a circle is also known as the circumference of the circle. The formula for calculating the circumference is expressed as:

C = 2πr

where

r is the radius

From the given diagram

r = 46/2 = 23m

C = 2(3.14)(23)
C = 144.44m

Find the perimeter of the rectangle

P = 2(l+w)

p = 2(46+150)
P = 2(196)
P =392m

The perimeter of the inside track = 144.44 + 392

The perimeter of the inside track = 536.44m

Hence the perimeter of inside of the track is 536.44m

Learn more on perimeter of composite shape here: brainly.com/question/16247505

#SPJ1

7 0
2 years ago
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