Find the 73rd term of the arithmetic sequence -28, -41, -54, ...

Mathematics

1 answer:

PolarNik [594]2 years ago

3 0

Answer:

the 73rd term of the arithmetic sequence is -964.

Step-by-step explanation:

The common difference in this arithmetic sequence is 13. This is obtained by subtracting 28 from 41. The first term is a(1) = -28.

The arithmetic sequence formula is a(n) = a(1) + d(n - 1), where d is the common difference and -28 the first term.

Then, in this case, a(n) = -28 - 13(n - 1), and

a(73) = -28 - 13(73 - 1) = -964

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Question 1(Multiple Choice Worth 1 points)

Stolb23 [73]

so, they already used 4,885.78 this month, but whatever all five family members can use total for a month is 7,250.50, so since they already used 4,885.78, they have left 7,250.50 - 4,885.78 = 2364.72.

$\bf \begin{array}{lllllll} \textit{amount all five}&&\textit{amount they}&\textit{must be}&\textit{amount allowed}\\ \textit{members can use}&&\textit{already used}&\textit{equals or less}&\textit{per month}\\\\ 5x&+&4,885.78&\leqslant&7,250.50 \end{array}$