Find the 73rd term of the arithmetic sequence -28, -41, -54, ...

Mathematics

1 answer:

PolarNik [594]1 year ago

3 0

Answer:

the 73rd term of the arithmetic sequence is -964.

Step-by-step explanation:

The common difference in this arithmetic sequence is 13. This is obtained by subtracting 28 from 41. The first term is a(1) = -28.

The arithmetic sequence formula is a(n) = a(1) + d(n - 1), where d is the common difference and -28 the first term.

Then, in this case, a(n) = -28 - 13(n - 1), and

a(73) = -28 - 13(73 - 1) = -964

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The cash drawer of the market contains $227. There are six more $5 bills than $10 bills. The number of $1 bills is two more than

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There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

Step-by-step explanation:

There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

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