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Juli2301 [7.4K]
3 years ago
11

If a vertical line passes through a graph only once the relation is considered to be a function. True or false?

Mathematics
2 answers:
kotykmax [81]3 years ago
6 0
This is True -----------
Anni [7]3 years ago
6 0
True, that is known as the verteical line test, baicaly it tests if there is only 1 y value corsponting with 1 x value

true
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4 0
3 years ago
What is the square of 16
Morgarella [4.7K]

Answer:

Square root of 16 = 4

Square of 16 = 256

Hope this helps :)

Have a great day !

5INGH

Step-by-step explanation:

6 0
4 years ago
Arrange the parabolas with respect tonthe postion of their vertices from left to right
agasfer [191]

Answer:

The correct answer for this question is this one:


If the x position of the vertex for f(x) is k then : 


1. f(k) => 4x+3=k, x = (k-3)/4 = (k/4)-(3/4) 

2. x = k+3 

3. x = (k+1)/2 = (k/2)-(1/2) 

4. x = 2(k+2) = 2k+4 

5. x = k+7 

6. x = k-3 

7. x = k-2 


So the order depends on the original position of the vertex k, e.g for k=0 the positions would be: 


1. -3/4 

2. 3 

3. -1/2 

4. 4 

5. 7 

6. -3 

7. -2 


So, therefore, the order would be 6 7 1 3 2 4 5



6 0
3 years ago
The figure shows circle C with tangent lines QR and SR.
nadya68 [22]

Answer:

1. is true

2. false

3. true

Step-by-step explanation:

4 0
3 years ago
Help me with this pleaae
marissa [1.9K]

Answer:

(D) 30pi inches

Step-by-step explanation:

First, we use the given volume, the given height, and the formula of the volume of a cylinder to find the radius of the base. Then we use the radius of the base to find the circumference of the base.

volume = \pi r^2 h

volume = 6750 \pi~in.^3

We set the formula equal to the volume and replace h with 30 in.

\pi r^2 h = 6750 \pi~in.^3

\pi r^2 \times 30 ~in. = 6750 \pi~in.^3

Divide both sides by 30pi in.

r^2 = 225 ~in.^2

Take the square root of each side.

\sqrt{r^2} = \sqrt{225 ~in.^2}

r = 15~in.

The radius of the base is 15 in.

Now we use the radius of the base and the formula of the circumference of a circle to find the answer.

circumference = 2 \pi r

circumference = 2 \pi \times 15~in.

circumference = 30 \pi ~in.

6 0
3 years ago
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