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tangare [24]
2 years ago
13

Because the numerator and denominator of the fraction are equivalent, the value of the fraction is __________ o Multiplying by 1

does not change the quantity, but using an equivalence will change the units (or label) o In order for units to cancel they must be in _____________________________ of the fraction.
Mathematics
1 answer:
kotykmax [81]2 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

A fraction is the ratio of the numerator to the denominator. It is given as:

Fraction = numerator / denominator.

If both the numerator and denominator are equal then:

numerator = denominator

Fraction = numerator / denominator = numerator / numerator = 1

When using fractions with units, if you want the units to be canceled out the both the numerator and the denominator must have the same units.

Because the numerator and denominator of the fraction are equivalent, the value of the fraction is 1.  Multiplying by 1 does not change the quantity, but using an equivalence will change the units (or label) o In order for units to cancel they must be in both numerator and denominator of the fraction,

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Factor by using the perfect-square trinomial formula. <br><br> 100x^2+20x+1
a_sh-v [17]
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then find what 2 numbers multiply to get 100 and add to get 20

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split the center term up
100x^2+10x+10x+1
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(100x^2+10x)+(10x+1)
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3 years ago
Read 2 more answers
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
vodka [1.7K]

Answer:

a) v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

b)  0

c) a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

Step-by-step explanation:

For this case we have defined the following function for the position of the particle:

x(t) = t^3 -6t^2 +9t -5 , 0\leq t\leq 10

Part a

From definition we know that the velocity is the first derivate of the position respect to time and the accelerations is the second derivate of the position respect the time so we have this:

v(t) =x'(t) = \frac{dx}{dt} = 3t^2 -12t +9

a(t) = x''(t) = v'(t) =6t-12

Part b

For this case we need to analyze the velocity function and where is increasing. The velocity function is given by:

v(t) = 3t^2 -12t +9

We can factorize this function as v(t)= 3 (t^2- 4t +3)=3(t-3)(t-1)

So from this we can see that we have two values where the function is equal to 0, t=3 and t=1, since our original interval is 0\leq t\leq 10 we need to analyze the following intervals:

0< t

For this case if we select two values let's say 0.25 and 0.5 we see that

v(0.25) =6.1875, v(0.5)=3.75

And we see that for a=0.5 >0.25=b we have that f(b)>f(a) so then the function is decreasing on this case.  

1

We have a minimum at t=2 since at this value w ehave the vertex of the parabola :

v_x =-\frac{b}{2a}= -\frac{-12}{2*3}= -2

And at t=-2 v(2) = -3 that represent the minimum for this function, we see that if we select two values let's say 1.5 and 1.75

v(1.75) =-2.8125< -2.25= v(1.5) so then the function sis decreasing on the interval 1<t<2

2

We see that the function would be increasing.

3

For this interval we will see that for any two points a,b with a>b we have f(a)>f(b) for example let's say a=3 and b =4

f(a=3) =0 , f(b=4) =9 , f(b)>f(a)

The particle is moving to the right then the velocity is positive so then the answer for this case is: 0

Part c

a(t) = x''(t) = v'(t) =6t-12

When the acceleration is 0 we have:

6t-12=0, t =2

And if we replace t=2 in the velocity function we got:

v(t) = 3(2)^2 -12(2) +9=-3

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3 years ago
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o-na [289]
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By the 66- 95 - 99.7 % rule it is: 99.7% of the test group.
0.977 * 500 = 498.5
Answer:
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The Senior class held an election for class president. Pamela received three (3) votes for every two (2) votes Angela received.
likoan [24]

Answer:

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Step-by-step explanation:

Divide 69 by 3

69 / 3 = 23

Take it times two.

23 x 2 = 46

Proportion

\frac{3}{2} =\frac{69}{x}

Cross multiply and solve for x.

6 0
3 years ago
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