The first three terms of sequence are 9 , 6 , 3
<em><u>Solution:</u></em>
Given the recursive function f(n) = f(n - 1) - 3
Where f(1) = 9
To find: First three terms of sequence
Substitute n = 2 , n = 3 and n = 4 in given recursive function
When n = 2
f(n) = f(n - 1) - 3
f(2) = f(2 - 1) - 3
f(2) = f(1) - 3
f(2) = 9 - 3 = 6
f(2) = 6
Thus second term is 6
When n = 3
f(3) = f( 3 - 1) - 3
f(3) = f(2) - 3
f(3) = 6 - 3 = 3
f(3) = 3
Thus the third term is 3
When n = 4
f(4) = f( 4 - 1) - 3
f(4) = f(3) - 3
f(4) = 3 - 3
f(4) = 0
Thus the fourth term is 0
Thus first three terms of sequence are 9 , 6 , 3
Answer:
d = 
Step-by-step explanation:
The distance formula is d = 
Plug in the points.
d = 
Solve
d = 
Simplify by separating 18 into 9x2
d = 
Take the square root of 9 to finish simplifying
d = 
Answer:
I have actually done this before, I got it right and I chose C!
hope this helps. love u guys!
Answer:
(3x + 4)(x - 1)
Step-by-step explanation:
3x^2 + x - 4
use middle term break method
we need two number which gives 12 when multiplied and 1 when subtracted
3x^2 + (4 - 3)x - 4
3x^2 + 4x - 3x - 4
x(3x + 4) -1(3x + 4)
(3x + 4)(x - 1)
I think the answer is substitution property of equality because you are substituting 9 for y as y=9.