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3 years ago

What dose square meters means

2 answers:

8 0

Okay, so a meter is a measure in length. Like a foot, or an inch. To square a measure of length, four equal measures of length (such as a meter) are put together to form a square. This is used for things like construction, or home refurbishing. Ex. 'My kitchen floor is 26 square meters'

Julli [10]3 years ago

4 0

It's a way to say the area of a place.

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Answer CORRECTLY !!!!! Will mark brainliest !!!!

mash [69]

Answer:

g(q) = $\frac{5q}{8}$

Step-by-step explanation:

Given

- 7q + 12r = 3q - 4r

Rearrange making r the subject

Add 7q to both sides

12r = 10q - 4r ( add 4r to both sides )

16r = 10q ( divide both sides by 16 )

r = $\frac{10q}{16}$ = $\frac{5q}{8}$ , thus

g(q) = $\frac{5q}{8}$

4 0

3 years ago

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DUE ASAP AT 10:30 5 ( x - 1 ) = 28 - 6x A 3 B 7 C 10 D -7

Nostrana [21]

Answer:

Step-by-step explanation:

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3 years ago

Dans un repère du plan, on donne les points (−2 ; 3), (6 ; 2) (−1 ; 0).

kondor19780726 [428]

Answer:

faut-il faire les ponits avec le pallergrom de (−2 ; 3), (6 ; 2) (−1 ; 0) ?

Step-by-step explanation:

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3 years ago

Evaluate the interval (Calculus 2)

Darya [45]

Answer:

$2 \tan (6x)+2 \sec (6x)+\text{C}$

Step-by-step explanation:

Fundamental Theorem of Calculus

$\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))$

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

$\displaystyle \int \dfrac{12}{1-\sin (6x)}\:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Terms multiplied by constants}\\\\$\displaystyle \int a\:\text{f}(x)\:\text{d}x=a \int \text{f}(x) \:\text{d}x$\end{minipage}}$

If the terms are multiplied by constants, take them outside the integral:

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)}\:\:\text{d}x$

Multiply by the conjugate of 1 - sin(6x) :

$\implies 12\displaystyle \int \dfrac{1}{1-\sin (6x)} \cdot \dfrac{1+\sin(6x)}{1+\sin(6x)}\:\:\text{d}x$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{1-\sin^2(6x)} \:\:\text{d}x$

$\textsf{Use the identity} \quad \sin^2 x+ \cos^2 x=1:$

$\implies \sin^2 (6x) + \cos^2 (6x)=1$

$\implies \cos^2 (6x)=1- \sin^2 (6x)$

$\implies 12\displaystyle \int \dfrac{1+\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

Expand:

$\implies 12\displaystyle \int \dfrac{1}{\cos^2(6x)}+\dfrac{\sin(6x)}{\cos^2(6x)} \:\:\text{d}x$

$\textsf{Use the identities }\:\: \sec \theta=\dfrac{1}{\cos \theta} \textsf{ and } \tan\theta=\dfrac{\sin \theta}{\cos \theta}:$

$\implies 12\displaystyle \int \sec^2(6x)+\dfrac{\tan(6x)}{\cos(6x)} \:\:\text{d}x$

$\implies 12\displaystyle \int \sec^2(6x)+\tan(6x)\sec(6x) \:\:\text{d}x$

$\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}$

$\boxed{\begin{minipage}{6 cm}\underline{Integrating $ \sec kx \tan kx$}\\\\$\displaystyle \int \sec kx \tan kx\:\text{d}x= \dfrac{1}{k}\sec kx\:\:(+\text{C})$\end{minipage}}$

$\implies 12 \left[\dfrac{1}{6} \tan (6x)+\dfrac{1}{6} \sec (6x) \right]+\text{C}$

Simplify:

$\implies \dfrac{12}{6} \tan (6x)+\dfrac{12}{6} \sec (6x)+\text{C}$

$\implies 2 \tan (6x)+2 \sec (6x)+\text{C}$

Learn more about indefinite integration here:

brainly.com/question/27805589

brainly.com/question/28155016

3 0

2 years ago

It takes 2 workers 6 days to paint a mansion. How many days would it take 4

marishachu [46]

Answer:

2 workers = 6 days

4 workers = 3 days

Step-by-step explanation:

If it takes 2 workers 6 days, if you seep up the process with 4 workers, you would divide the days by 2 because you multilpied the workers by 2. So, it would take 3 days with 4 workers. I hope that makes sence.

4 0

3 years ago