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kozerog [31]
3 years ago
10

Please help me with #16 I am really bad at doing fractions

Mathematics
1 answer:
emmasim [6.3K]3 years ago
3 0
To see if it's a right triangle we need to determine if a²+b²=c²
(\frac{3}{20})² + (\frac{1}{5})² = \frac{1}{4}
\frac{9}{400} + \frac{1}{25} = \frac{1}{16}
\frac{9}{400} + \frac{16}{400} = \frac{25}{400}
\frac{25}{400} = \frac{25}{400}

So it is a right triangle
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Point A is located at (-5, 2) on a coordinate grid. Point A is translated 8 units to the right and 3 units up to create point A.
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The closest distance between point A and point A' is 8.5 ⇒ B

Step-by-step explanation:

Let us revise the translation of a point

  • If the point (x , y) translated horizontally to the right by h units  then its image is (x + h , y)
  • If the point (x , y) translated horizontally to the left by h units  then its image is (x - h , y)
  • If the point (x , y) translated vertically up by k units  then its image is (x , y + k)
  • If the point (x , y) translated vertically down by k units  then its image is (x , y - k)

∵ Point A is located at (-5 , 2)

∵ Point A is translated 8 units to the right and 3 units up

- That means add x-coordinate by 8 and add y-coordinate by 3

∴ Point A' located at (-5 + 8 , 2 + 3)

∴ Point A' located at (3 , 5)

The distance between two points (x_{1},y_{1}) and (x_{2},y_{2})

is d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

∵ Point a = (-5 , 2) and point A' = (3 , 5)

∴ x_{1} = -5 and x_{2} = 3

∴ y_{1} = 2 and y_{2} = 5

- Substitute these values in the rule of the distance

∵ d=\sqrt{(3--5)^{2}+(5-2)^{2}}

∴ d=\sqrt{(3+5)^{2}+(3)^{2}}

∴ d=\sqrt{(8)^{2}+(3)^{2}}

∴ d=\sqrt{64+9}=73

∴ d = 8.544 ≅ 8.5

The closest distance between point A and point A' is 8.5

Learn more:

You can learn more about the distance between two points in brainly.com/question/6564657

#LearnwithBrainly

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