Answer:
The numerical limits for a D grade is between 57 and 64.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:

D: Scores below the top 80% and above the bottom 7%
Between the 7th and the 100 - 80 = 20th percentile.
7th percentile:
X when Z has a pvalue of 0.07. So X when Z = -1.475.




So 57
20th percentile:
X when Z has a pvalue of 0.2. So X when Z = -0.84.




So 64
The numerical limits for a D grade is between 57 and 64.
Let X be a random variable representing the score of of student.
P(X ≥ 50) = 1 - P(X < 50) = 1 - P(z < (50 - 42)/8) = 1 - P(z < 1) = 1 - 0.84134 = 0.15866
I'm not sure how you want me to answer this question? WHat are you tryng to solve for?
Answer:
Set Y has the smaller mean. Mean means average.
Step-by-step explanation:
Set X: 20.45+28+22.25+16.5+13+18.05=118.25 divide that by 6. 118.25/6= 19.71
Set Y: 21+6+5+24+9+40= 95 divide that by 6. 95/6= 15.83
Answer:
1) 9.69
2) 87.36
3) 171.42
4) 18.75
5) 16.29
Step-by-step explanation:
Treat each value's full price as x. then, all of the values are (2/3)x. To get (2/3)x back to x, we must multiply (2/3)x*(3/2)=x. Multiply each of the questions given by 3/2 or 1.5