Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
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When I do what the problem statement says, I get 47° for the left angle and 58° for the right one. They are not congruent.
The GCF is 2
Pull out 2 from each number:
2(2n + 5)
Hope this helps!
Answer:
(-11, 1)
Step-by-step explanation:
x-values are horizontal and y-values are vertical
so add -4 to -7 to get -11
add 0 to 1 to get 1
new point is at (-11,1)
