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luda_lava [24]
3 years ago
5

I need the help of identifying the constant term and numerical coefficient in this expression

Mathematics
2 answers:
Serggg [28]3 years ago
6 0
Number coefficient 2
aalyn [17]3 years ago
3 0

Answer:

constant term:n

numerical coefficient:2

Step-by-step explanation:

a numerical coefficient is a fixed number that is multiplied to a variable. So in the expression, the numerical coefficient would be 2

A constant term is something in an algebraic expression that does not change which is n

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Sue practice playing the piano for 46 minutes she ended at 7:35 what time did she begin
sleet_krkn [62]
She began at 6:49.  

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7 0
3 years ago
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How do u solve this step by step and also pls don’t answer unnecessarily
kari74 [83]
You have to have one side equal x so I’ll solve one from each section

e) x = 2

5x = 12 - x
add x to both sides
6x = 12
divide both sides by 6
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k) x = 3

15x + 4 = 10x + 19
move the 4 to the other side by subtracting on both sides
15x = 10x + 15
subtract 10x from both sides
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6 0
3 years ago
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In 2004, there were 19,396 bulldogs registered by the American Kennel Club. Approximately 86% of this number were registered in
ss7ja [257]
To solve this problem you must find 86% of 19,396.
To do this, let's start by turning 86% a decimal to multiply.
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Now, we multiply 0.86 by 19,396.
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The question says about, so we need to round it.
When rounded we get 16681.
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Hope this helped you! :)

6 0
3 years ago
Simplify 4(2x^3y^4)^4/2(2x^2y^6)^3. Show your work. Please help ASAP!!
vovikov84 [41]

Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

=2[(2)^4(x^{12})(y^{16})](2)^{-3}(x^{-6})(y^{-18})  (  ( using the property a^m=\frac{1}{a^{-m}} )

=2[2^{4-3}x^{12-6}y^{16-18}]( using the property a^m.a^n=a^{m+n} )

=2[2^1x^6y^{-2}]

=\frac{4x^6}{y^2} ( using the property a^m=\frac{1}{a^{-m}} )

Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

5 0
4 years ago
Please help guys!! This is my first time downloading this app :)
Crazy boy [7]

Answer:

u^{6}

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} ⇔ a^{(m+n)} , then

u³ × u³ = u^{(3+3)} = u^{6}

7 0
3 years ago
Read 2 more answers
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