I think the answer is c I hope this help
Yes true. the answer is true
Answer:
the answer is D.
Step-by-step explanation:
can you pls give me brainlest
The cardinality of the union between two sets is given by

In fact, if an element is in both A and B, it is counted in both N(A) and N(B), so we're counting it twice. By subtracting the cardinality of the interserction, we're taking back one of these "extra-counted" element, and the count is correct. In your case, the numbers are

This means that the two sets cover, without repetitions, 43 of the 66 elements in the sets. So, there are

elements which are in neither A nor B
L = W+4
A = L x W
A = w + 4 x w
A = w² +4w