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ikadub [295]
3 years ago
8

a flower garden is 4 feet longer than its width. write a polynominal that represents the area of the garden

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0
L = W+4
A = L x W
A = w + 4 x w
A = w² +4w
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Round 12.034 to the nearest tenth
vovangra [49]
The answer is 12.  Thanks (;
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3 years ago
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The profit per acre from a grove of orange trees is given by x(190 − x) dollars, where x is the number of orange trees per acre.
nasty-shy [4]

Answer:

P(x) = 190 x -x^2

In order to maximize the last equation we can derivate the function in term of x and we got:

\frac{dP}{dx} = 190 -2x

And setting this derivate equal to 0 we got:

\frac{dP}{dx} = 190 -2x=0

And solving for x we got:

x = 95

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

P(x=95)= 95(190-95)= 95*95 = 9025

Step-by-step explanation:

For this case we have the following function for the profit:

P(x) = x(190-x)

And we can rewrite this expression like this:

P(x) = 190 x -x^2

In order to maximize the last equation we can derivate the function in term of x and we got:

\frac{dP}{dx} = 190 -2x

And setting this derivate equal to 0 we got:

\frac{dP}{dx} = 190 -2x=0

And solving for x we got:

x = 95

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

P(x=95)= 95(190-95)= 95*95 = 9025

7 0
3 years ago
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The radius of a cone is increasing at a constant rate of 7 meters per minute, and the volume is decreasing at a rate of 236 cubi
storchak [24]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

V = \frac{1}{3}\pi r^{2}h

Differentiate the equation with respect to time t, such that

\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)

To differentiate the product,

Let r² = u, so that

\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)

Then, using product rule

\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}]

Since u = r^{2}

Then, \frac{du}{dr} = 2r

Using the Chain's rule

\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}

∴ \frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})]

Then,

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

Now,

From the question

\frac{dr}{dt} = 7 m/min

\frac{dV}{dt} = 236 m^{3}/min

At the instant when r = 99 m

and V = 180 m^{3}

We will determine the value of h, using

V = \frac{1}{3}\pi r^{2}h

180 = \frac{1}{3}\pi (99)^{2}h

180 \times 3 = 9801\pi h

h =\frac{540}{9801\pi }

h =\frac{20}{363\pi }

Now, Putting the parameters into the equation

\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}]

236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)]

236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386]

708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}

708 = 30790.75 \frac{dh}{dt} + 76.36

708 - 76.36 = 30790.75\frac{dh}{dt}

631.64 = 30790.75\frac{dh}{dt}

\frac{dh}{dt}= \frac{631.64}{30790.75}

\frac{dh}{dt} = 0.021 m/min

Hence, the rate of change of the height is 0.021 meters per minute.

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3 years ago
Write 45/30 in simplest form​
RideAnS [48]

Answer:

1 1/2

Step-by-step explanation:

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Now simplify

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Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r
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Answer:  

0.32 decay

Step-by-step explanation:

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3 years ago
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