For a
polynomial with real cofieints, if a+bi is a root, a-bi is also a
root
zeros,
i and 5-i
passes
through origin means 0 is also a zero
get
plus and minus of the roots
i,
-1, 5-i, 5+i and 0 are roots
for a
poly with roots, r1,r2,r3,r4,r5, the facotred form is
(x-r1)(x-r2)(x-r3)(x-r4)(x-r5)
sub
the roots
(x-i)(x-(-i))(x-(5-i))(x-(5+i))(x-0)=
(x-i)(x+i)(x-5+i))(x-5-i))(x)=
x(x^2+1)(x^2-10x+26)=
x^5-10x^4+27x^3-10x^2+26x
the
polynomial is f(x)=x^5-10x^4+27x^3-10x^2+26x
Answer:
x=3.5
the answer is 3.5 because 7 divided by 2 is 3.5
Answer:
add all and devide by the amount of numbers so in this case 0+5+6+7+7 devided by 5
Step-by-step explanation:
5.its correct answer. 6.complimentary 7.supplimentary
Answer:


Step-by-step explanation:
<h3><u>Question 12</u></h3>
Find the slope of the line by substituting two points from the given table into the slope formula.
<u>Define the points</u>:
- Let (x₁, y₁) = (2, 7)
- Let (x₂, y₂) = (3, 13)

Substitute the found slope and point (2, 7) into the point-slope formula to create an equation of the line:




<h3><u>Question 17</u></h3>
Given:
Therefore, two points on the line are:
The y-intercept is the y-value when x = 0.
Therefore, the y-intercept of the line is -2.

Substitute the y-intercept and the point (4, 3) into the slope-intercept formula and solve for <em>m</em> to find the slope:




Therefore, the equation of the line is:
