I am a number greater than 40,000 and less than 60,000:
40,000 < n < 60,000
This means that:
n = 10,000n₁ + 1,000n₂ + 100n₃ + 11n₄
And also:
4 ≤ n₁ < 6
0 ≤ n₂ ≤ 9
0 ≤ n₃ ≤ 9
0 ≤ n₄ ≤ 9
My ten thousands digit is 1 less than 3 times the sum of my ones digit and tens digit:
n₁ = 3*2n₄ - 1
n₁ = 6n₄ - 1
This means that:
n = 10,000*(6n₄-1) + 1,000n₂ + 100n₃ + 11n₄
n = 60,000n₄ - 10,000 + 1,000n₂ + 100n₃ + 11n₄
n = 60,011n₄ - 10,000 + 1,000n₂ + 100n₃
<span>My thousands digit is half my hundreds digit, and the sum of those two digits is 9:
n</span>₂ = 1/2 * n₃
<span>
n</span>₂ + n₃ = 9
<span>
Therefore:
n</span>₂ = 9 - n₃
<span>
Therefore:
9 - n</span>₃ = 1/2 * n₃
<span>
9 = 1/2 * n</span>₃ + n₃
<span>
9 = 1.5 * n</span>₃
<span>
Therefore:
n</span>₃ = 6
<span>
If n</span>₃=6, n₂=3.
<span>
This means that:
</span>n = 60,011n₄ - 10,000 + 1,000*3 + 100*6
n = 60,011n₄ - 10,000 + 3,000 + 600
n = 60,011n₄ - 6,400
Therefore:
0<n₄<2, so n₄=1.
If n₄=1:
n = 60,011 - 6,400
n = 53,611
Answer:
53,611
she will need 54 ft of crown molding. and since its $3.10 per foot, $167.40 will be the total cost.
Answer:
Long wings: 0
Short wings: 100
Step-by-step explanation:
Genotype of the flies: ww
The cross will yield the genotype ww and the flies will express the recessive phenotype which is short wings.
The probability for long wings will be 0 as there is no dominant allele present. The probability for short wings will be 100 as all the flies will have short wings.
Hope that helps.
Answer:
z(s) is in the rejection zone , therefore we reject H₀
We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%
Step-by-step explanation:
We have a prortion test.
P₀ = 37 % P₀ = 0,37
sample size = n = 100
P sample proportion = P = 47 % P = 0,47
confidence interval 95 %
α = 0,05
One tail-test (right tail) our case is to show if sample give enough information to determine if proportion of individual who attended college is higher than the proportion found by Harper´s index.
1.-Hypothesis:
H₀ null hypothesis P₀ = 0,37
Hₐ alternative hypothesis P₀ > 0,37
2.-Confidence interval 95 %
α = 0,05 and z(c) = 1.64
3.-Compute of z(s)
z(s) = [ P - P₀ ] /√(P₀Q₀/n) ]
z(s) = [ ( 0,47 - 0,37 ) / √0.37*0,63/100
z(s) = 0,1 /√0,2331/100 ⇒ z(s) = 0,1 /0,048
z(s) = 2.08
4.-Compare z(s) and z(c)
z(s) > z(c) 2.08 > 1.64
5.-Decision:
z(s) is in the rejection zone , therefore we reject H₀
We have enough evidence to claim the proportion of individuals who attended college and believe in extraterrestrials is bigger than 37%
Answer:
h=9
Step-by-step explanation:
18h+30=192
18h=162
h=9
