Two points of the slope y=(2x+2) - 3 are (-1,0), (0,1)
4πrsquare= 2πrsquare+2πrh
2πrsquare=2πrh
R=h
So h=16/2=8mm
Ok so first equate all the three equations whether by substituting or by eliminating then choose the one das not the answer
The equation may also have one common root or no real roots. This gives the maximum number of points where the parabola<span> intersect as </span>2<span>. ... When that is the case, the twp </span>parabolas<span> intersect at 4 </span>distinct<span> points. The maximum number of points of intersection of </span>two distinct parabolas<span> is 4.</span>
