Joe has some pocket money. He spends 90% of it. He has fifty pence left. How much pocket money did he have?

A local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle. In o

Mandarinka [93]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ = 22 ounces

Alternate Hypothesis, $H_A$ : $\mu\neq$ 22 ounces

(b) The value of the test statistic is -2.687.

(c) The critical values are -1.96 and 1.96.

(d) We conclude that Reject $H_0$ since the value of the test statistic is less than the negative critical value.

Step-by-step explanation:

We are given that a local bottler in Hawaii wishes to ensure that an average of 22 ounces of passion fruit juice is used to fill each bottle.

He takes a random sample of 65 bottles. The mean weight of the passion fruit juice in the sample is 21.54 ounces. Assume that the population standard deviation is 1.38 ounce.

Let $\mu$ = average ounces of passion fruit juice used to fill each bottle.

(a) So, Null Hypothesis, $H_0$ : $\mu$ = 22 ounces {means that the average of 22 ounces of passion fruit juice is used to fill each bottle}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 22 ounces {means that the average different from 22 ounces of passion fruit juice is used to fill each bottle}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean weight of the passion fruit juice = 21.54 ounces

$\sigma$ = population standard deviation = 1.38 ounce

n = sample of bottles = 65

So, test statistics = $\frac{21.54-22}{\frac{1.38}{\sqrt{65} } }$

= -2.687

(b) The value of z test statistics is -2.687.

(c) Since, in the question we are not given with the level of significance so we assume it to be 5%. Now, at 5% significance level the z table gives critical values of -1.96 and 1.96 for two-tailed test.

Since our test statistics does not lie within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that Reject $H_0$ since the value of the test statistic is less than the negative critical value which means that the average different from 22 ounces of passion fruit juice is used to fill each bottle.

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3 years ago

Which of the following are solutions to the system graphed below.

Kisachek [45]

Weird. I think you just need to look if the point falls on the shaded area. But only (-5,5) does ...

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3 years ago

If $1,000 is invested in an account that pays 5% interest compound annually, an expression that represents the amount in the acc

KengaRu [80]

Hello! So the formula for compound interest is P(1 + r)^t, where r = rate, P = principal, and t = time (years). C is out, because you multiply the rate and principal together to get the price, not add. You raise the decimal to a certain power, based on the amount of years. You add 1 to the rate. 5% in decimal form is 0.05 and you must add 1 to the amount, which eliminated B. The only answer that works is A, because it shows the correct formula. The answer is A.

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Read 2 more answers

Manny bought a brand new car for $29,750. The car depreciates in value by 12% each year. Find the value of the car after 6 years

Arte-miy333 [17]

Answer: $13,846.02

Step-by-step explanation:

The car cost $29,750 when it was first bought.

It will then depreciate at a rate of 12% per year. This means that the value of the car reduces by 12% per year.

To find the value of the car in the 6th year, you can use the compound interest formula:

= Value of car * ( 1 - rate) ^ no. of years

= 29,750 * ( 1 - 12%)⁶

= ‭13,816.021581824‬

= $13,846.02

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2 years ago

Someone please help 4(x-2)-3>-3(-2+6)+2

NNADVOKAT [17]

Answer:

Fraction form: x > 1/4

Decimal form: x > 0.25

Step-by-step explanation:

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3 years ago