Answer:
Step-by-step explanation:
This question is asking us to find where sin(2x + 30) has a sin of 1. If you look at the unit circle, 90 degrees has a sin of 1. Mathematically, it will be solved like this (begin by taking the inverse sin of both sides):
![sin^{-1}[sin(2x+30)]=sin^{-1}(1)](https://tex.z-dn.net/?f=sin%5E%7B-1%7D%5Bsin%282x%2B30%29%5D%3Dsin%5E%7B-1%7D%281%29)
On the left, the inverse sin "undoes" or cancels the sin, leaving us with
2x + 30 = sin⁻¹(1)
The right side is asking us what angle has a sin of 1, which is 90. Sub that into the right side:
2x + 30 = 90 and
2x = 60 so
x = 30
You're welcome!
Answer:
<u>x</u><u> </u><u>is</u><u> </u><u>3</u>
Step-by-step explanation:
Answer:
16
Step-by-step explanation:
you do 2+2 which is 4 then 8/2 is 4 and you multiple 4*4
The answer will be B because all three angles of the triangles add up to180 degrees, and we already know the total of two other angles are 100 degrees, which made the unknown angles have 80 degrees. Hope it help!
-2x^4 + 24x^2 - 10
u have 3 terms.....and since u are only dealing with 1 variable with the highest exponent being 4, then what u have here is a 4th degree trinomial.
U have a lead coefficient of -2.
Ur constant term is -10
And ur middle term (24x^2) has a degree of 2
a cubic binomial.....a binomial has 2 terms and it being cubic means the highest term has a degree of 3
example would be : x^3 - 4
how many constants can a polynomial have ? I am not sure about this one...I wanna say 1 because u can simplify it if it has more then 1...but I am not 100% sure on this one
3x^2 + 6xy -10x^5 + y^6 - 10x^3y^5
when u have a polynomial with more then 1 variable, such as this one, the degree is not the highest exponent, it is the highest term.....-10x^3y^5...u add the exponents....so this term has a degree of 8, and it is the highest one in this problem....so this is an 8th degree polynomial with 5 terms
